Answer:option A
Multiple reactants are used to form one product.
Answer:
Explanation:
Explanation:
As you know, the empirical formula tells you what the smallest whole number ratio that exists between the atoms that make up a compound is.
In your case, you know that the empirical formula is
NH Cl
2
, which means that the regardles of how many atoms of each element you get in the actual compound, the ratio that exists between them will always be
1:2:1.
What you actually need to determine is how many empirical formulas are needed to get to the molecular formula.
Notice that the problem provides you with the molar mass of the compound. This means that you can use the molar mass of the empirical formula to determine exactly how many atoms you need to form the compound's molecule.
molar mass empirical formula×n=molar mass compound
To get the molar mass of the empirical formula, use the molar masses of its constituent atoms
14.0067 g/mol+2×1.00794 g/mol+35.453 g/mol=51.48 g/mol≈
51.5 g/mol
This means that you have
51.5g/mol×n=51.5g/mol
As you can see, you have
n=1.
This means that the empirical formula and the molecular formula are equivalent,
NH Cl.
2
Answer:
Compound that tastes sour
Answer:
Explanation:
Use Dalton's law and the vapor pressure of water at 23.0 o C to correct the pressure to units of atmoshperes.
PT = Poxygen +Pwater
At 23.0 o C the vapor pressure of water is 21.1 mmHg. (This can be found on a vapor pressure table.)
762 mmHg = Poxygen + 21.1 mmHg
Poxygen = 762 mmHg - 21.1 mmHg
Poxygen =741 mmHg
Convert the corrected pressure to atmospheres.
(741 mmHg) (1 atm / 760 mmHg) = 0.975 atm
Use the ideal gas law to find out how many moles of gas were produced:
PV = nRT (remember to put volume in liters and temperature in Kelvin)
(0.975 atm) (.193 L) = n (.0821 L atm / mol K) (298 K)
n = (0.975 atm) (.193 L) / (.0821 L atm / mol K) (298 K)
n = 7.69 X 10-4 mol
Use the number of moles and the molecular weight of oxygen to find out how many grams of oxygen were collected.
(7.69 X 10-4 mol) (32.0 g / 1 mol) = 2.46 X 10-2 g
