Answer:
Explanation:
3BaCl₂(aq) + 2Na₃PO₄(aq) = Ba₃(PO₄)₂ + 6NaCl(aq)
3 x 208 g = 624 g 2 x 164 g = 328 g
328 g of Na₃PO₄ reacts with 624 g of BaCl₂
.611 g of Na₃PO₄ reacts with 624 x .611/328 g of BaCl₂
624 x .611/328 g = 1.16 g of BaCl₂
BaCl₂ available is .504 g which is less than required .
Hence BaCl₂ is limiting reagent .
I believe it is D.
Since something with a high temperature has a higher kinetic energy, it would make sense for the energy of the molecules in the ground to increase. This is because the increasing temperature of the ground allows for the molecules to become faster in motion.
Answer:
if this is balanced or unbalanced equations then this one is balanced since there is 2 H on each side and 2 Cl's on each side
Explanation:
Answer:
See detailed explanation.
Explanation:
Hello!
In this case, for the reaction:
It is known that the equilibrium constant tends to be greater than 1; therefore, it is a reaction that tends to go rightwards towards the formation of hydrogen iodide.
a) Here, since the reaction tends to form the product, it is clear that the initial concentration of iodine and hydrogen will decrease as the reaction reaches equilibrium in order to increase the concentration of hydrogen iodide.
b) Yes, it stops at the point in which the following expression:
![\frac{[HI]^2}{[I_2][H_2]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BI_2%5D%5BH_2%5D%7D)
Equals the equilibrium constant.
Best regards!
Answer:
7 SigFigs
Explanation:
If you're asking how many sigfigs there are in the number, it's seven significant figures.
