1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lilit [14]
3 years ago
11

Can you help me find the slope! (30 points)

Mathematics
2 answers:
slavikrds [6]3 years ago
8 0
Slope formula = y2 - y1 / x2 - x1

-1 - 0.5 = -1.5
-5 - 2.5 = -7.5
-1.5/-7.5 = .2

.2 simplified is 1/5

elena-s [515]3 years ago
5 0

Answer:

1/5  

Step-by-step explanation:

change of y over change of x will get you 1.5/7.5 which is 0.2 or 1/5


You might be interested in
PLEASE HELP ASAPP SHOW UR WORK i’ll mark brainliest!!
ASHA 777 [7]

Answer:

c = 15n + 50

Step-by-step explanation:

the total cost = $15 for each person ( n ) + a $50 flat fee

6 0
3 years ago
If f(x) = 3x + 7, find:<br> f(-2) = [ ? ]
devlian [24]

Answer:

1

Step-by-step explanation:

Plug in -2.

f(x) = -6+7

f(x) = 1

3 0
3 years ago
10x+2=9x3<br> what is the answer
yKpoI14uk [10]

Answer:

8.5

Step-by-step explanation:

10x+2=9x(3)

10x+2=27x

2=17x

x=8.5

6 0
2 years ago
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
2 years ago
NEED CORRECT ANSWER PLEASE! THANKS:)
-BARSIC- [3]
The answer is B. (2x + 5)(x + 1)You could answer this by expanding each answer until you found one that matched 2x^2 + 7x + 5, but I will only show how the answer expands:
2x × x = 2x^2
5 × x = 5x
2x × 1 = 2x
5 × 1 = 5

So in total those brackets expand to 2x^2 + 7x + 5. I hope this helps!
6 0
3 years ago
Other questions:
  • All help is appreciated! If sin²(32°) +cos² (M) = 1, then M equals?
    12·1 answer
  • Can someone help me with this please?
    6·1 answer
  • HELP I'VE ASKED THIS QUESTION 4 TIMES NOW PLEASE HELP
    7·2 answers
  • WILL MARK BRAINLIEST FOR BEST ANSWER
    7·2 answers
  • A baseball team won 40% of its first 30 games. The team then won 65% of its next 60 games. Approximately what percent of the gam
    6·1 answer
  • Can you please show work and put answer <br><br> 2 (n + 5) = -2
    12·2 answers
  • What is the answer to this (in attached photo)
    11·2 answers
  • The length of a rectangular field is 6 metres longer than its width. If the area of the field is 72 square metres, What are the
    10·1 answer
  • An African elephant weighed 209 lbs when it was born. Baby elephants gain an average of 38 lbs per week.
    15·1 answer
  • Write a division equation that represents the question: how many 3/8s are in 5/4​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!