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4 years ago

Which interval on the graph could be described as linear increasing? A B C D

Mathematics

2 answers:

NNADVOKAT [17]4 years ago

7 0

<span>A decreasing
B increasing
C stay the same
D </span>decreasing

Answer is B.

Klio2033 [76]4 years ago

7 0

Answer:

Step-by-step explanation:

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I don't know how to simplify

In-s [12.5K]

(5-2/x)/4-3/x^2

after simplifying these
(5x-2)/x(4x^2-3)/x^2
x(5x-2)/(4x^2-3)
5x^2-2x/4x^2-3

now u can solve it

6 0

3 years ago

(ASAP) Billie & Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen ye

jeka94

Answer:

Billie's age = x = 17 years

Tony's age = y = 31 years

Step-by-step explanation:

Let

Billie's age = x

Tony's age = y

Twice Billie’s age decreased by 3 is Tony’s age.

y = 2x - 3..... Equation 1

Tony is fourteen years older than Billie.

x = y - 14

We substitute y - 14 for x in Equation 1

y = 2x - 3..... Equation 1

y = 2(y - 14) - 3

y = 2y - 28 - 3

y - 2y = -28 - 3

-y = -31

y = 31 years

Solving for x

x = y - 14

x = 31 - 14

x = 17 years.

Therefore:

Billie's age = x = 17 years

Tony's age = y = 31 years

4 0

3 years ago

Read 2 more answers

The question is :

gtnhenbr [62]

64 lb = 29.0299 KG
Rounding to the nearest hundredth, it's 29.03 KG

4 0

3 years ago

NEED THE ANSWER ASAP!

Schach [20]

Answer:

my nut is ytellow

Step-by-step explanation:

3 0

3 years ago

Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3

nlexa [21]

Answer:

$(x,y) = (5,-6)$

Step-by-step explanation:

$\underline{\textbf{Determinant of a matrix.}}\\\\\text{For a}~ 2 \times 2 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2\\b_1&b_2 \end{vmatrix} = a_1b_2 - a_2b_1\\\\\\\text{For a}~ 3 \times 3 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2&a_3\\ b_1&b_2&b_3\\ c_1&c_2&c_3 \end{vmatrix} = a_1\begin{vmatrix} b_2&b_3\\c_2&c_3 \end{vmatrix} - a_2 \begin{vmatrix} b_1&b_3\\c_1&c_3 \end{vmatrix}+ a_3 \begin{vmatrix} b_1&b_2\\c_1&c_2 \end{vmatrix}\\\\\\$

$~~~~~~~~~~~~~~~~~~=a_1(b_2c_3-b_3c_2) -a_2(b_1c_3-b_3c_1) +a_3(b_1c_2-b_2c_1)$

$\underline{\textbf{Cramer's Rule to solve a system of two equations.}}\\\\\text{Consider the system of two equations:}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_1x + b_1 y= c_1\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_2x +b_2 y = c_2\\\\\text{Here,}\\\\x = \dfrac{D_x}{D}= \dfrac{\begin{vmatrix} c_1&b_1\\c_2&b_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\\\ y= \dfrac{D_y}{D}= \dfrac{\begin{vmatrix} a_1&c_1\\a_2&c_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\$

$\underline{\textbf{Solution:}}\\\\~~~~~~~~~~~~~~~~~~~~~~~8x-5y = 70~~~~~~...(i)\\\\~~~~~~~~~~~~~~~~~~~~~~~9x +7y = 3~~~~~~~...(ii)\\\\\text{Applying Cramer's rule:}\\\\x = \dfrac{D_x}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 70& -5 \\3&7 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{70(7) -(-5)(3)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{490+15}{56+45}\\\\\\~~=\dfrac{505}{101}\\\\\\~~=5$

$y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6$

$\textbf{Hence, the solution to the system of equation is}~ (x,y) = (5,-6)$

7 0

2 years ago