1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergeu [11.5K]
3 years ago
15

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch.

Mathematics
1 answer:
balandron [24]3 years ago
4 0
To properly visualize the given, we transform them into equation form rather than words.
                          f(x) = sqrt (x)
                          g(x) = 8(sqrt(x))
From these, it may be observed that g(x) is 8 times of f(x). These transformation is in the value of y and is scaling. Because it is multiplied by a a whole number, the transformation is vertical scaling that involves multiplying the y-coordinate by 8. 
You might be interested in
Identify which of the following is not equivalent to 2 3/4.
mezya [45]

The figure that is not equivalent to 2¾ is 2¼ × 2½. That is option B.

<h3>Simplification of equivalent fractions</h3>

Simplification is a process that is used to make a fraction appear in its simplest forms.

The fraction given is = 2¾

The simplification of the fraction= 2^3/4 = 2

But simplification of 2¼ × 2½ is equal to;

2¼= 0.5

2½= 1

Therefore 2¾ is not equivalent to 2¼ × 2½ when simplified.

Learn more about fraction here:

brainly.com/question/78672

#SPJ

6 0
2 years ago
20. Solve for x when 18x = 2/3 Provide your answer as a fraction. please do not do website​
serious [3.7K]
18x/18 = 2/3 • 18
Flip reciprocal of 18 which is 1/18 so it would be 2/3 • 1/18 the 2 and 18 can be simplified when cross multiples so it would then be 1/3 • 1/9 which is x=1/27
3 0
3 years ago
What construction does the image below demonstrate?
MA_775_DIABLO [31]

Answer:(D) A regular hexagon inscribed in a circle

Step-by-step explanation:

Since here the length of  arcs FAD, EAC DAB, and CAG from the points E, point D, point C and  Point B respectively have the same measurement. (Shown in given diagram)

Therefore, All chords of circle A that are FE, ED, DC, CB, BG, and GF have the same length.

Therefore here we get a figure which having 6 edges and inscribed in the circle A.

Which is a  regular hexagon BCDEFG.

Therefore, Option D) is correct.



8 0
4 years ago
Read 2 more answers
What is the 13th term of the geometric sequence<br> 4, 12, 36, 108, ...?
bogdanovich [222]

Answer: 2,125,764

Step-by-step explanation:

You can use the equation y=ar^n-1 to find the 13th term where a is the starting term, r is the common ratio, and n is the nth term

The next number is 12/4=3 times greater than the first. So if this sequence is a geometric one, then the next term must be 12*3=36. This is true, and the next term must be 36*3=108, which is also true. Therefore this sequence is a geometric one and its common ratio is 3. Therefore the equation is:

y=4*3^(n-1)

Substitute 13 for n:

y=4*3^(13-1)

y=4*3^12

y=2125764

Therefore, the 13th term of this geometric sequence is 2,125,764

7 0
2 years ago
Hello<br> I have to write at least 20 words to say hi.
maksim [4K]
Hi

I have to write at least 20 words to say hello.
7 0
3 years ago
Other questions:
  • A moving company charges $30 plus $0.15 Per mile to rent a moving van another company charges $15 plus $0.20 per mile to rent th
    6·1 answer
  • First person gets brainliest 4 <br><br> 45+9
    9·2 answers
  • 6/2(1+2)+1-1+1-1+1-1​
    12·2 answers
  • Solve for x.
    7·1 answer
  • If r(x)=4x^2-3x+7, Find r(2a^2)
    14·1 answer
  • A magazine costs $3 and a book cost $7 if you want to spend exactly $45 on reading this month and you need to buy eight magazine
    9·1 answer
  • ) (i) Simplify:<br>Permudahkan:-<br>9 + 3t - 4​
    11·1 answer
  • PLEASE HELPP!! DID I DO IT RIGHT???
    7·1 answer
  • Question 19 (4 points)
    14·2 answers
  • PLEASE HELP
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!