Factor out the common term; 3
(3(x + 1))^2 = 36
Use the Multiplication Distributive Property; (xy)^a = x^ay^a
3^2(x + 1)^2 = 36
Simplify 3^2 to 9
9(x + 1)^2 = 36
Divide both sides by 9
(x + 1)^2 = 36/9
Simplify 36/9 to 4
(x + 1)^2 = 4
Take the square root of both sides
x + 1 = √4
Since 2 * 2 = 4, the square root of 2 is 2
x + 1 = 2
Break down the problem into these 2 equations
x + 1 = 2
x + 1 = -2
Solve the first equation; x + 1 = 2
x = 1
Solve the second equation; x + 1 = -2
x = -3
Collect all solutions;
<u>x = 1, -3</u>
Answer:
Step-by-step explanation:
Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.
Probability for any one to be defective as of now is 
a) 
b) After I draw we have 35 good ones and 9 defective
P(F/E) =
c) P(G/EF)
This is the probability for iii bulb to be good given I and II are goog.
Once I and ii are good we have 43 bulbs with 34 good ones

P=650
R= 5% annually= 0.05
T=1 month=1/12 year
Sl=Prt=650*0.05*1/12= $2.70
So the answer would be 2.7 or 2.70
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