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Musya8 [376]
2 years ago
5

The length of a rectangle is 7mm longer than its width. It’s perimeter is more than 62mm. Let W equal the width of the rectangle

, write an inequality and solve it

Mathematics
2 answers:
olasank [31]2 years ago
6 0
First of all, what is the equation for the perimeter of a rectangle? 
2(l + w) = p
Since we know the perimeter (p) is greater than 62 we can say:
2(l + w) > 62
It is also given that the length is 7 mm longer than the width, so we know the value of the length in terms of w (the width).
w = w
l = w + 7
Substitute l with (w + 7) into the equation:
2[(w + 7) + w] > 62
Now combine like terms in the parentheses
2(2w + 7) >62
Distribute the 2 into the terms in the parentheses
4w + 14 > 62
Subtract both sides by 14
4w > 62 - 14
Combine like terms
4w > 48
Divide both sides by 4
w > 48

Final answer: w > 48
Hope this helps!
lutik1710 [3]2 years ago
4 0
This is the answer to the question.

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