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mixer [17]
3 years ago
10

If a baker doubles recipe that call for 6-23 of flour how many cups of flour will be needed in all

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0
Unsure of what you mean by "6-23."  There's no subtraction in this problem.  

If you meant "6/23," then "doubling" that results in 12/23 cups.  Still, that does not look right.  Go back and ensure that you have copied down the original problem exactly.

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Isaiah put a 100 gram weight on a pan balance. how many 10 gram weights does he need to balance the scale
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Answer=10 10gram weights
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Julia’s service at a beauty salon was $72.60, before tax. The sales tax rate was 8%. If she added 20% of amount before tax as a
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6 0
3 years ago
AC=(5x+12) and BD =8x? Can somebody help me to slove it
AleksAgata [21]
To solve this equation from the information given above, I ordered it 5x+12=8x. To solve, I subtracted 5x from each side, canceling the 5x to your left, leaving only the number 12. 8x minus 5x equals 3x. Take 3x and divide on both sides. 3x/3x cancels the 3, leaving 12/3 equals 4. Finally, x equals 4.
3 0
3 years ago
Pls help me help me pls ​
grin007 [14]

Answer:

Point B

Step-by-step explanation:

Lines given:

  • y= 2/5x - 1/2
  • y= -1/3x +2/3

x coordinate of intersection of given lines is:

  • 2/5x - 1/2= -1/3x+2/3
  • 2/5x+1/3x= 2/3 +1/2
  • 6/15x+5/15x= 4/6+3/6
  • 11/15x=7/6
  • x= 7*15/11*6
  • x= 35/22

For this value of x, the value of y is:

  • y= 2/5*35/22 - 1/2
  • y=14/22- 1/2
  • y= 3/22

As per graph point (35/22, 3/22) is point B

4 0
3 years ago
Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n

then the sequence solves the recurrence relation.

4 0
3 years ago
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