Answer:
a) 0.1558
b) 0.7983
c) 0.1478
Step-by-step explanation:
If we suppose that small aircraft arrive at the airport according to a <em>Poisson process</em> <em>at the rate of 5.5 per hour</em> and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:
(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?
(b) What is the probability that at least 4 arrive during a 1-hour period?
(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?
If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now
and we want <em>P(X ≥ 75) = 1-P(X<75)</em>. But
hence
P(X ≥ 75) = 1-0.852 = 0.1478
Answer:
first number is 4
second number is 0
Step-by-step explanation:
y = 1st number
x = 2nd number
system of equations:
5y + 4x = 20
4y + 2x = 16
I multiplied the second equation by -2 to eliminate the 'x-values'
-2(4y + 2x = 16) = -8y - 4x = -32
now add to 1st equation: <u>5y + 4x = 20</u>
-3y = -12
y = 4
solve for 'x':
5(4) + 4x = 20
20 + 4x = 20
4x = 0
x = 0
The process of long division is shown here.
Answer: c = -2
Explanation:
-2c + 6 = 10
-2c = 10 - 6
-2c = 4
c = 4/-2
c = -2