Answer:
f(g(5)) = 64
g(f(5)) = 28
Step-by-step explanation:
Given that f(x) = x^2 and g(x) = x+3
f(g(x) = f(x+3)
f(x+3) = (x+3)^2
f(g(x)) = (x+3)^2
f(g(5)) = (5+3)^2
f(g(5)) = 8^2
f(g(5)) = 64
b) g(f(x)) = g(x^2)
g(f(x)) = x^2 + 3
g(f(5)) = 5^2 +3
g(f(5)) = 25 + 3
g(f(5)) = 28
Hence the value of g(f(5)) is 28
Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
F(x)=-3(x)+4
Therefore this implies that we must put the -4 where we see an X on the equation
F(-4)=-3(-4)+4
=16
Answer: 15 yards
Step-by-step explanation:
From the question, we have been informed that the Steelers are on the Cowboys' fifteen-yard line. Using the place value mat to calculate how much farther Steelers need to travel to score a touchdown goes thus:
Since the play is 15 yards from the Cowboys end-zone, therefore Steelers need to travel 15 yards for them score a touchdown.
Pretty sure the answer is $600
Hope this helps
