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3 years ago

A triangle has a base of nine meters and a hight of 8 meters, what is the area of the triangle

Mathematics

2 answers:

Stolb23 [73]3 years ago

6 0

B- the area is 0.5xbasexheight

ANEK [815]3 years ago

6 0

B.36 square meters ( um I don’t know what else to put so I’m doing this)

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-4x-6=-5y+9

wlad13 [49]

4x-5y=-15
That’s the answer your welcome

3 0

3 years ago

6(5x-3) what is the answer to this

Zarrin [17]

Answer:

= 30x − 18

Step-by-step explanation:

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2 years ago

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The data set shows the number of practice free throws players in a basketball competition made and the number of free throws the

Mila [183]

Answer-

The exponential model best fits the data set.

Solution-

x = input variable = number of practice throws

y = output variable = number of free throws

Using Excel, Linear, Quadratic and Exponential regression model were generated.

The best fit equation and co-efficient of determination R² are as follows,

Linear Regression

Quadratic Regression

Exponential Regression

The value of co-efficient of determination R² ranges from 0 to 1, the more closer its value to 1 the better the regression model is.

Now,

Therefore, the Exponential Regression model must be followed.

5 0

3 years ago

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

3 years ago

Read 2 more answers

The distance that an object covered in time was measured and recorded in the table below.True/False: The distance covered is dir

Sedaia [141]

Answer:

true

Step-by-step explanation:

did the test

5 0

3 years ago