Answer:
9.577 mm.
Step-by-step explanation:
We have been given that the diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm.
Let us find the circumference of quarter and nickel using circumference of circle formula.
, where r represents radius of the circle.
Since we know that diameter of circle is 2 times its radius, so let us find radius of quarter and nickel by dividing their diameter by 2.
Therefore, circumference of quarter is 76.1764 mm.
Let us find circumference of nickel.
Let us subtract circumference of nickel from circumference of quarter.
Therefore, the distance around a quarter is 9.577 millimeters bigger than a nickel.
Answer:
-2 , -2 , 0 , 1 , 2 , 4 , 7 , 8 , 9 , 12
Step-by-step explanation:
Order each number from least to greatest. Note that if the number is numerically larger and attached is a negative sign (-), then it is towards the least. If it does not have a negative sign, it leans towards the most.
Your answer:
-2 , -2 , 0 , 1 , 2 , 4 , 7 , 8 , 9 , 12
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Answer: p=9
explanation: 6 reds + 3 blues = 9.
Answer:
1.36+3+(32)(2)
=57
error is that 6 is the wrong answer
Answer:
(0,-2)
Step-by-step explanation:
one way to solve...
3x - y = 2 --> *4
-2x + 4y = -8
multiply the first equation by 4
12x - 4y = 8
-2x + 4y = -8
-----------------
10x = 0
x = 0
y = -2
this method is called elimination
another way to solve...
3x - y = 2 simplify for y to get y = 3x - 2
-2x + 4y = -8 substitute y into this equation to solve for x
-2x + 4(3x - 2) = -8
-2x + 12x - 8 = -8
10x = 0
x = 0
y = -2
substitution
alsoo if there are options, just plug in the numbers to the correct variables
