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abruzzese [7]
3 years ago
6

Joe had a summer job that pays $7.00 an hour and he worked 15 and 35 hours every week. His weekly salary can be modeled by the e

quation: s = 7H, wear a is his weekly salary and h is the number of hours he worked in a week. Describe the domain and range for this problem using appropriate notation.
Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0

Correct question is;

Joe had a summer job that pays $7.00 an hour and he worked between 15 and 35 hours every week. His weekly salary can be modeled by the equation: S = 7h, where S is his weekly salary and h is the number of hours he worked in a week.

What is the reasonable Domain and Range?

Answer:

Domain is: 15 ≤ x ≤ 35

Range is: 105 ≤ x ≤ 245

Step-by-step explanation:

We are told that Joe works between 15 and 35 hours every week.

This means that he works at least 15 hours or at most 35 hours a week.

Thus, domain is; 15 ≤ x ≤ 35

We are told that his weekly salary can be modeled by the equation: s = 7H

Where s is salary and H is number of hours worked per day.

Thus;

Lower range is; s = 7 × 15 = $105

While higher range is; s = 7 × 35 = $245

Thus, range is 105 ≤ x ≤ 245

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4 years ago
Which of these statements is true for f(x) = 2.3*?
Marina86 [1]

The true statement for f(x) = 2(3)^x is the y-intercept is (0, 2).

<h3>How to determine the true statement?</h3>

The function is given as:

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f(0) = 2(3)^0

Evaluate

f(0) = 2

This means that the y-intercept of f(x) = 2(3)^x is (0,2)

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6 0
2 years ago
F(x)= x^2 translated 4 units down
Oduvanchick [21]

Answer:

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zeros- (-2,2)

y-intercept- (-4)

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4 0
3 years ago
Paul invested three times as much money in the account paying 5% interest then he did in an account paying 4% of the total inter
noname [10]

Given

Paul invested three times as much money in the account paying 5% interest then he did in an account paying 4%.

Total interest paid was $475

Find out  he invest in each.

To proof

Let us assume that Paul invested  in an account paying 4% be = x

As given in the question

Paul invested three times as much money in the account paying 5% interest then he did in an account paying 4%.

Let us assume that Paul invested  in an account paying 5% be = 3x

Total interest paid = $475

First convert 4% in the decimal form

=\frac{4}{100}

= 0.04

First convert 5% in the decimal form

=\frac{5}{100}

= 0.05

Than the equation become in the form

0.04x + 0.05 × 3x = 475

0.04x + 0.15x = 475

0.19x = 475

x = $2500

Paul invested  in an account paying 4% be = $2500

Paul invested  in an account paying 5% be = $7500

Hence proved






5 0
3 years ago
PLEASE HELP FOR BRAINLIEST:
jeka57 [31]

Answer:

Step-by-step explanation:

You have 2 equations and 3 unknowns (A, x, y). You could use any value for A and it would be correct because then you could solve for the other unknowns. See picture for many exampleS.

Please mark Brainliest when able.

6 0
3 years ago
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