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Andrews [41]
3 years ago
6

Match the sequence with the correct indicated term.

Mathematics
1 answer:
algol133 years ago
3 0
1) an = a1 + d*(n-1) => a20 = -4 + (-9)*19 = -4 - 171 = - 175
1) ---> C)

2) a81 = 20 + 4*80 = 340;
2) ---> A)

3) a12 = ?
3) ---> B) or D).
You might be interested in
A service club is selling raffle tickets for 2.50 each to raise money for a charity. Vanessa has 34.75 to spend on raffle ticket
posledela

Answer:

13 Raffle tickets

Step-by-step explanation:

Cost for one riffle ticket = 2.50

Total money of Vanessa budgeted for riffle ticket : 34.75

Greatest number of riffle ticket, venessa can with with 34.75

I'll like us to divide 34.75 by 2.5 to get the exact value.

Therefore,

34.75 / 2.5

= 13.9

It therefore implies that, Vanessa will buy a maximum of 13 riffle tickets and still have a change of 2.25

4 0
3 years ago
The ordered pair (−3,−6) is a solution for the first equation, and it is a solution for the second equation. Therefore, (−3,−6)​
Alisiya [41]
False. If x=-3 and y=-6 and you substitute them into the equation they do not add up

7 0
2 years ago
Read 2 more answers
A phone company charges $0.06 per minute for local calls and $0.15 per minute for international calls. When your bill comes, it
solmaris [256]
Let's assume two variables x and y which represent the local and international calls respectively. 

x + y = 852 = total number of minutes which were consumed by the company (equation 1)
0.06*x+ 0.15 y =69.84 = total price which was charged for the phone calls (Equation 2)
 from equation 1:-
x=852 -y (sub in equation 2)
0.06 (852 - y) + 0.15 y =69.84

51.12 -0.06 y +0.15 y =69.84 (subtracting both sides by 51.12)
0.09 y =18.74
y= 208 minutes = international minutes (sub in 1) 
208+x=852 (By subtracting both sides by 208)
x = 852-208 = 644 minutes = local minutes
6 0
3 years ago
Graph<br> &gt; -4.<br> &gt;<br> -5<br> -4<br> -3<br> -2<br> -1<br> 0<br> 1<br> 2<br> 3
igor_vitrenko [27]

Answer:

cant under stand thoes

Step-by-step explanation:

sorry

8 0
3 years ago
Graph the first six terms of a sequence where a1=5 and r=1.25
emmainna [20.7K]
The sequence above is geometric progression. 
The nth term of such sequence is given by;

Tn = ar∧(n-1),
Where a⇒first term and
            r⇒common ratio

So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5 
      2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
      3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
       4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
       5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
       6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909
7 0
3 years ago
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