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Arada [10]
3 years ago
15

Jermaine got an 84% on a math test. If the test had 25 questions, how many

Mathematics
1 answer:
julia-pushkina [17]3 years ago
6 0

Answer:

21

Step-by-step explanation:

why do you use points when you could literally just search it up

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Is angle SAM congruent to angle DEL if so identify the simularity postulate or theorem applies
atroni [7]

Answer:

yes

Step-by-step explanation:

yes because that is literally what he used

4 0
3 years ago
A model scale is 1 cm = 8m.<br> If the actual object is 40 meters, the model is<br> ____ cm long.
Dovator [93]

Answer:

Mmmmmmmmmmmmm.............

Step-by-step explanation:

MI no sabo amigo perdon

8 0
3 years ago
Read 2 more answers
At the beginning of October, you have $300 in your bank account. You get $25 of allowance each week. Your cousin has $200 in her
lys-0071 [83]

Answer:

20 weeks to have the same amount for both bank accounts

Step-by-step explanation:

brainliest plss?

6 0
2 years ago
Dilate ABC below using A as the center and a<br> scale factor of 2. Leave all construction marks?
irina1246 [14]
<h3>Answer: Check out the diagram below.</h3>

Explanation:

Use your straightedge to extend segment AB into ray AB. This means you'll have it start at A and go on forever through B. Repeat these steps to turn segment AC into ray AC.

The two rays join at the vertex angle A. Point A is the center of the universe so to speak because it's the center of dilation. We consider it an invariant point that doesn't move. Everything else will move. In this case, everything will move twice as much compared to as before.

Use your compass to measure the width of AB. We don't need the actual number. We just need the compass to be as wide from A to B. Keep your compass at this width and move the non-pencil part to point B. Then mark a small arc along ray AB. What we've just done is constructed a congruent copy of segment AB. In other words, we've just double AB into AB'. This means the arc marking places point B' as the diagram indicates.

The same set of steps will have us construct point C' as well. AC doubles to AC'

Once we determine the locations of B' and C', we can then form triangle A'B'C' which is an enlarged copy of triangle ABC. Each side of the larger triangle has side lengths twice as long.

Note: Points A and A' occupy the same exact location. As mentioned earlier, point A doesn't move.

8 0
3 years ago
Can you see an easy way to work out the value of <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%201%5E3%20%2B%202%5E3%20%2B%203%5E
Lina20 [59]

We have the sum of cubes identity

a^3 + b^3 = (a + b) (a^2 - ab + b^2)

and observing that 1 + 4 = 2 + 3, we have

1^3 + 4^3 = (1 + 4) (1^2 - 4 + 4^2) = 5 \times 13

and

2^3 + 3^3 = (2 + 3) (2^2 - 6 + 3^2) = 5 \times 7

Then

\sqrt{1^3+2^3+3^3+4^3+5^3} = \sqrt{5\times13 + 5\times7 + 5\times5^2} = \sqrt{5 \times (20 + 25)} \\\\ ~~~~~~~~ = \sqrt{5^2 \times (4 + 5)} = \sqrt{5^2\times9} = \sqrt{5^2\times3^2} = 5\times3 = \boxed{15}

Alternatively, we have the well-known sum of cubes formula

\displaystyle \sum_{i=1}^n i^3 = \frac{n^2(n+1)^2}4

The sum under the square root is this sum with n=5. Then

1^3+2^3+3^3+4^3+5^3 = \dfrac{5^2\times6^2}4 = 225 = 15^2

and so the square root again reduces to 15.

5 0
2 years ago
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