Question

A circular swimming pool has a radius of 15 ft. There is a path all the way around that pool that is three feet wide. A circle has a radius of 15 feet. A larger circle goes around the smaller circle that is 3 feet wide. What is the circumference of the outer edge of the path around the pool? Use 3. 14 for Pi. 56. 52 ft 94. 20 ft 113. 04 ft 114. 04 ft.

Answer 1

The circumference of the outer edge of the path around the pool is 113.04 ft.

What is the circumference?

The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.

Given

A circular swimming pool has a radius of 15 ft.

There is a path all the way around that pool that is three feet wide.

A circle has a radius of 15 feet.

A larger circle goes around the smaller circle that is 3 feet wide.

The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.

The radius of the outer edge of the path around the pool = 15 + 3

The radius of the outer edge of the path around the pool = 18ft

The circumference of the outer edge of the path around the pool is;

$\rm Circumference=2\pi r\\\\Circumference = 2\times 3.14 \times 18\\\\Circumference=113.04 \ ft$

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.

To know more about circumference click the link given below.

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