I got x=185
0.75(185)-18.50=0.65(185)
120.25=120.25
Answer: 0.01
Step-by-step explanation:
Let the events are :
C = paving stones found to be cracked.
D = paving stones found to be discolored.
Given : Total stones : T = 600 (i)
C = 15
D= 27
C'∩D'= 564 (ii)
Since C'∩D' = (C∪D)' = T- C∪D (iii)
From (i) , (ii)and (ii) , we have
564 = 600- C∪D
⇒ C∪D=600- 564= 36
Formula : C∩D= C+D- C∪D
Put values , we get
C∩D= 15+27-36=6
Now ,
The probability that it is both cracked and distorted is 0.01.
Answer:
See below ↓↓
Step-by-step explanation:
a₁ refers to the first term of the sequence.
That is clearly : a₁ = <u>6</u>
<u></u>
The formula for the nth term is :
- aₙ = a₁rⁿ⁻¹
- Common ratio (r) = quotient of consecutive terms
- r = -12/6 = -2
Therefore, the nth term is :
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614
