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mash [69]
2 years ago
15

What is the slope of a line parallel to y = 4/3x-2

Mathematics
1 answer:
den301095 [7]2 years ago
4 0

I'm not that sure but I want to help

Step-by-step explanation:

y=4/3×-2

y=2/3×

Divide 2/3×

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I'm have a little trouble figuring it out.​
saveliy_v [14]

Answer:

fourth option

Step-by-step explanation:

the answer should be the fourth option.

hope it helped you there?

3 0
3 years ago
Read 2 more answers
Courtney has a total of 88 stamps worth $15.56. Some are $0.25 stamps and some are $0.02 stamps. How many of each foes she have?
olganol [36]

Let x = # of 25-cent stamps

y = # of 2-cent stamps

{   x+ y = 88

{ 0.25x + 0.02y = 15.56

60 25-cent stamps 28 2-cent stamps

5 0
2 years ago
A square is sometimes a rhombus
Veseljchak [2.6K]

Answer:

This would be true.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A freight train departs from one train station to its destination at a constant speed. Suppose the distance the train is from th
barxatty [35]

Answer:

108 miles

Step-by-step explanation:

Given the points (0.5, 135) and (2,81)

Diatnce between two points :

D = √(x2 - x1)² + (y2 - y1)²

X1 = 0.5 ; y1 = 135 ; x2 = 2 ; y2 = 81

D = √(2^2 - 0.5^2) + (81^2 - 135^2)

D = √(4 - 0.25) + (6561 - 18225)

D = √3.75 −11664

D = 107.98263

D = 108 miles

6 0
3 years ago
Help algebra 2 please
kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

          = x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

          = x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

        = -5x³ + 2x² + 7x - 5x² + 2x + 7

        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

       =  -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

                = x*(x² + 2x + 4) - 2*(x² + 2x + 4)

                = x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

                = x³ + 2x² + 4x  -2x² -4x - 8

                = x³ - 8

2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}

7 0
3 years ago
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