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USPshnik [31]
3 years ago
6

Lin is 7 years younger than Adrian,

Mathematics
1 answer:
icang [17]3 years ago
8 0

Answer: Age of Lin is 12

Solution:

Let X= age of Maya

(X/2)+4= age of Adrian

((X/2)+4)-7= age of Lin

X+(X/2)+4+((X/2)+4-7)=61

X+.5X+4+.5X+4-7=61

2X+4+4-7=61

2x=61-8+7

2X=60

X=30 age of Maya

19= age of Adrian

Age of Lin is

=((X/2)+4)-7

=15+4-7

=12

To check if this is correct

<span>30+19+12=61</span>

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Question:
kykrilka [37]
What we know:
- number of meeting rooms = m
- chairs in each meeting room = 325

Since we need an equation to represent the number of chairs in m meeting rooms, we would multiply the amount of chairs per meeting room (325) by m. This amount is c. So the equation becomes:

c = 325m

Now the question asks for the amount of chairs if there are 7 meeting rooms in the hotel. To find this, substitute 7 for m into c = 325m.

c = 325m
c = 325(7)
c = 2275

Answer:
The equation is c = 325m, and the amount of chairs if m equals 7 is 2,275.
8 0
3 years ago
Read 2 more answers
For the following amount at the given interest rate compounded​ continuously, find​ (a) the future value after 9 ​years, (b) the
Stella [2.4K]

Answer:

(a) The future value after 9 ​years is $7142.49.

(b) The effective rate is r_E=4.759 \:{\%}.

(c) The time to reach ​$13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of P dollars is invested at a rate of interest r compounded continuously for t years, the compound amount is

A=Pe^{rt}

(a) From the information given

P=4700

r=4.65\%=\frac{4.65}{100} =0.0465

t=9 \:years

Applying the above formula we get that

A=4700e^{0.0465\cdot 9}\\A=7142.49

The future value after 9 ​years is $7142.49.

(b) The effective rate is given by

r_E=e^r-1

Therefore,

r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}

(c) To find the time to reach ​$13,000, we must solve the equation

13000=4700e^{0.0465\cdot t}

4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88

3 0
3 years ago
3. The dance club at school has 22 members. The dance coach wants to send four members to a special training on
diamong [38]

Answer:

a) a combination

b) The probability = 1 ÷ [ Number of ways to select the four dancers ]

Step-by-step explanation:

a) Here it is only required to calculate the number of ways to select the four dancers and the order of the dancers is not required i.e not important for us.

Hence, we will use a combination to select 4 out of 22 dancers

i.e ²²C₄

b) Since the dancers selected are 4 predetermined individuals

therefore,

number of ways to select selecting dancers Laura, Matthew, Lakiesha, and Santos will be '1'

Hence,

The probability = 1 ÷ [ Number of ways to select the four dancers ]

= 1 ÷ ²²C₄

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4 years ago
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stiks02 [169]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
1. Quadrilateral EFGH is an isosceles trapezoid. If mG is four times mH, what is mE? A)18° C)72° D)144° B)36°​
Maslowich

Answer:

<E = 36 degrees (Answer B)

Step-by-step explanation:

Recall that the addition of all internal angles in a quadrilateral must equal 360 degrees. Then we can write the equation that states this as:

<E + <F + <G + <H = 360

Notice as well that we are dealing with an isosceles trapezoid, so there is a symmetry along the line that passes through the midpoints of sides FG and EH (the two bases). That means that the measures of angles <F = <G  and <E = <H .

The previous equation then can be written as:

<H + <G + <G + <H = 360

Also, since we are told that <G = 4 <H, we can use this info in the equation as shown below:

<H + 4 <H + 4 <H + <H = 360

10 <H = 360

divide both sides by 10 to isolate <H

<H = 360 / 10

<H = 36

Since as we mentioned, <E equals <H, we can state that

the measure of <E = 36 degrees (Answer B)

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3 years ago
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