1.50s + 0.75f = 116.25
2f = s
1.50(2f) + 0.75f = 116.25
3f + 0.75f = 116.25
3.75f = 116.25
f = 116.25/3.75
f = 31...31 friday papers
2f = s
2(31) = s
62 = s <=== 62 sunday papers
What is the third quartile of this data set 20,21,24,25,28,29,35,36,37,43,44
SashulF [63]
Answer:
37
Step-by-step explanation:
The data set is in ascending order, thus the median is the middle value of the data set.
median = 29
The third quartile is the middle value of the data to the right of the median
= 37
CF of 24<span> = 1, 2, 3, 4, 6, 8, 12, </span>24<span>. CF of </span>64<span> = 1, 2, 4, 8, 16, 32, </span>64<span>. CF of </span>88<span> = 1, 2, 4</span><span>, 8, 11, 22, 44, </span><span>88
</span>
The width of the rectangle is 15in