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-Dominant- [34]
2 years ago
15

What is 4^3x5+6^2-34+78x2^4? They look terrible.

Mathematics
1 answer:
Tomtit [17]2 years ago
3 0

Answer:

They look AWSOME

Step-by-step explanation:

Honestly, I couldn't paint to save my life.

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The length of the sides of four triangles are given. Determine which triangle is not a right triangle.a.5 mm, 12 mm, 13 mmb.20 m
gizmo_the_mogwai [7]
For a right triangle, the sum of the squares of two shorter side should be equal to the square of the third side. The calculations for each choices are shown below. 

a. (5 mm)² + (12 mm)² = 169 mm²    ;    (13 mm)² = 169 mm²   ;     EQUAL
b. (20 mm)² + (48 mm)² = 2704 mm²   ; (52 mm)² = 2704 mm²  ;    EQUAL
c. (6 mm)² + (8 mm)² = 100 mm²       ;    (10 mm)² = 100 mm²   ;     EQUAL
d. (11 mm)² + (24 mm)² = 697 mm² ;  (26 mm)² = 676 mm²  ;  NOT EQUAL

Therefore, the answer is letter D. 
7 0
3 years ago
4b3 + 5c? Combine any like terms. If there are no like terms, rewrite the expression
sashaice [31]
There are no like terms in this expression
8 0
3 years ago
Read 2 more answers
Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

8 0
2 years ago
Denice is making 25 bouquets. 4/5 of the bouquets are roses and the rest are daisies. How many bouquets are daisies?
erica [24]

Answer:

5 of the bouquets are Daises.

Step-by-step explanation:

25 in all. 4/5 are Roses.

4/5 = Rose Bouquets  1/5 = Daisy Bouquets

4/5 = 20/25  

1/5 = 5/25

So 5 are Daises

7 0
3 years ago
Can someone help me out with this ? 8(1 - 8p) + 8p
goldfiish [28.3K]
8(1-8p) + 8p
8 - 64p + 8p
8 - 56p
8 = 56p
1/7 = p
6 0
2 years ago
Read 2 more answers
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