Given the function j(x)=x^2 and k(x)=-x^=7x-1

1 answer:

7 0

The question is incomplete.

The complete question is:

Given the functions j(x) = x² − 9 and k(x) = −x + 7, which operation results in a 3rd degree polynomial?

Answer: the multiplication of j(x) and k(x)

Explanation:

1) j(x) × k(x) = (x² − 9) ( − x + 7)

2) Use distributive propery:


(x²)(- x) + (x²) (7) + (-9)(-x) + (− 9) ( 7) = - x³ + 7x² + 9x - 63


The exponent of x is 3, hence this is a third degree polynomial.

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