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maw [93]
3 years ago
14

Fiona has $18 to spend. She spent $4.25, including tax, to buy a notebook. She needs to save $9.75, but she wants to buy a snack

. If crackers cost $0.50 per package including tax, what inequality would show the maximum number of packages that Fiona can buy
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

4.25+9.75+0.5x≤18

Step-by-step explanation:

4.25+9.75+0.5x≤18

14+0.5x≤18

0.5x≤4

x≤8

She can buy at most 8 packs of crackers.

Hope this helps :)

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Please help this for my pre calculus finals
dsp73

Answer:

a) It will take 17.71 years

b) It will take 17.58 years

c) I will earn $6.60 more in compound continuously

Step-by-step explanation:

a) Lets talk about the compound interest

- The formula for compound interest is A = P (1 + r/n)^(nt)

, Where:

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial deposit)

- r = the annual interest rate (decimal)

- n = the number of times that interest is compounded per unit t

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound quarterly

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ n = 4

∴ t = ?

∵ A = P (1 + r/n)^(nt)

∴ 6000 = 2000 (1 + 0.0625/4)^4t ⇒ divide both sides by 2000

∴ 3 = (1.015625)^4t ⇒ insert ㏑ for both sides

∴ ㏑(3) = ㏑(1.015625)^4t

∵ ㏑(a)^b = b ㏑(a)

∴ ㏑(3) = 4t ㏑(1.015625) ⇒ divide both sides by ㏑(1.015625)

∴ 4t = ㏑(3)/㏑(1.015625) ⇒ divide both sides by 4

∴ t = [㏑(3)/㏑(1.015625)] ÷ 4 = 17.71

* It will take 17.71 years

b) Lets talk about the compound continuous interest  

- Compound continuous interest can be calculated using the formula:

  A = P e^rt  

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial amount)

- r = the interest rate  

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound continuously

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ t = ?

∵ A = P e^rt  

∴ 6000 = 2000 e^(0.0625 t) ⇒ divide both sides by 2000

∴ 3 = e^(0.0625 t) ⇒ insert ㏑ to both sides

∴ ㏑(3) = ㏑[e^0.0625 t]

∵ ㏑(e^a) = a ㏑(e) ⇒ ㏑(e) = 1 , then ㏑(e^a) = a

∴ ㏑(3) = 0.0625 t ⇒ divide both sides by 0.0625

∴ t = ㏑(3)/0.0625 = 17.5778

* It will take 17.58 years

c) If t = 5 years

# The compound quarterly:

∵ A = P (1 + r/n)^(nt)

∴ A = 2000 (1 + 0.0625/4)^(4×5)

∴ A = 2000 (1.015625)^20 = $2727.08

# Compound continuously

∵ A = P e^(rt)

∴ A = 2000 e^(0.0625×5) = $2733.68

∴ I will earn = 2733.68 - 2727.08 = $6.60

* I will earn $6.60 more in compound continuously

5 0
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timofeeve [1]
The gcf would be 12 because both 12 and 36 can be divided by 12 and it is the highest number
4 0
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Which sequence could be described by the explicit definition: t_n=2^n+1t n = 2 n + 1
yuradex [85]

Answer:

2. 27

3. Option C. 3, 5, 9, 17, 33, ...

Step-by-step explanation:

2. The sequence is defined by the explicit function t_{n} = 2^{n}  - n

Therefore, the 5th term i.e. t_{5} of the sequence.

t_{5} = 2^{5}  - 5 = 32 - 5 = 27 (Answer)

3. The explicit definition is t_{n} = 2^{n}  + 1

Hence, t_{1} = 2^{1}  + 1 = 3

t_{2} = 2^{2}  + 1 = 5

t_{3} = 2^{3}  + 1 = 9

t_{4} = 2^{4}  + 1 = 17

Therefore, the option C is the right sequence. (Answer)

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ohaa [14]
Your answer would be 176.25%
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Mrac [35]

Answer:

Missing Value Is 4 .

Step-by-step explanation:

According To The Question, We Have

  • A model with 4rows*4squares & 4rows*7squares

        Equation is 16+28 = X*(4+7)

        Solve the above Equation, We get 44=X*11 ⇔ X=4

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