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Solnce55 [7]
3 years ago
15

The perimeter of a rectangle is 100 yd. if its width is four times its length, what is the area?

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

<span>Length = l</span>

<span>
Width = w</span>

<span>
Perimeter = p = 100

</span>

<span>Perimeter of rectangle = 2(l+w)</span>

<span>
100 = 2 (4w + w)</span>

<span>
100 = 2(5w)</span>

<span>
100 = 10w</span>

<span>
100/10 = w</span>

<span>
10 = w</span>

<span>
w =  10



Area of rectangle = length * width</span>

<span>
a = l*w</span>

<span> a = 4w*w</span>

<span>
a = 4w^2............(1)</span>

<span>
Put the value of w in (1)</span>

<span>
a = 4(10)^2</span>

<span>
a= 4(100)</span>

<span>
a = 400 yd^2</span>

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