Find the area of a sector of a circle with radius 6 centimetre if angle of sector is 60 degree

Mathematics

1 answer:

Gnesinka [82]3 years ago

6 0

Answer:

Step-by-step explanation:

$area=\frac{\pi r^2 \times\theta}{360} =\frac{\pi 6^2 \times 60}{360} =6 \pi \approx 18.85~ cm^2$

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Natali5045456 [20]

Answer: -1/343

Step-by-step explanation:

-7(-7)^-4

First, re-write as positive exponents:

-7(-1/7^4)

Next, simplify:

-1/7^3 (you can simplify using exponent rules)

Simplify 7^3 :

7(7)(7)

49(7)

343.

Insert to original expression:

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frozen [14]

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The height of an object tossed upward with an initial velocity of 120 feet per second is given by the formula h = −16t2 + 120t,

AleksAgata [21]

Answer:

7.5 seconds

Step-by-step explanation:

$h = - 16 {t}^{2} + 120t \\ \because \: we \: have \: to \: find \: the \: time \: required \: \\ for \: the \: object \: to \: return to \: its \: \\ point \: of departure. \\ \therefore \: plug \: h = 0 \: in \: the \: given \: euation. \\ \therefore \: 0 = - 16 {t}^{2} + 120t \\ \therefore \:16 {t}^{2} - 120t = 0 \\ \therefore \:8t(2t - 15) = 0 \\ \therefore \:8t = 0 \: \: or \: \: (2t - 15) = 0 \\ \therefore \:t = \frac{0}{8} \: or \: t = \frac{15}{2} \\ \therefore \:t = 0 \: or \: t = 7.5 \\ \because \: t = 0 \: is \: not \: possible \\ \huge \purple{ \boxed{ \therefore \: t = 7.5 \: seconds}}$