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Rus_ich [418]
3 years ago
14

Find the area of a sector of a circle with radius 6 centimetre if angle of sector is 60 degree​

Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer:

Step-by-step explanation:

area=\frac{\pi r^2 \times\theta}{360} =\frac{\pi 6^2 \times 60}{360} =6 \pi \approx 18.85~ cm^2

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Write and solve a story problem about gathering three kinds of vegetables. Use 10 partners.
marta [7]

Answer:

Cameron and Rebecca are organizing a lunch for their friends. Within the dishes to be served, they will prepare a tomato, carrot and broccoli salad. The number of tomatoes and carrots are 10-partners and the total amount of vegetables is 12. If we increase the number of broccoli by three and decrease the number of tomatoes by two, the amount of tomatoes and broccoli will also be 10-partners. What is the number of tomatoes, carrots and broccoli bought by Cameron and Rebecca?

<u>Cameron and Rebecca purchased 7 tomatoes, 3 carrots and 2 broccoli.</u>

Step-by-step explanation:

Number of tomatoes = x

Number of carrots = 10 - x

Number of broccoli = y

System of Equations:

x + 10 - x + y = 12

y = 12 - 10

y = 2

x - 2 + y + 3 = 10 (If we increase the number of broccoli by three and decrease the number of tomatoes by two, the amount of tomatoes and broccoli will also be 10-partners)

x + 1 + y = 10

x + y = 9

y = 9 - x

Substitution of y:

x + 10 - x + y = 12

x + 10 - x + 9 - x = 12

-x + 19 = 12

-x = 12 - 19

x = 7 ⇒ 10 - x = 3

<u>Cameron and Rebecca purchased 7 tomatoes, 3 carrots and 2 broccoli.</u>

5 0
3 years ago
Does anyone know his one answer!?!
earnstyle [38]
The answer is the the second one
3 0
3 years ago
Multiplying polynomials find the product . <br> 2x(-2x-3)
skad [1K]


2x(-2x-3)=

=2x*(-2x)+2x*(-3)=

=-4x²-6x

7 0
3 years ago
Agiven line has the equation 10x+27-2
bagirrra123 [75]

Answer:

y=7 so all of the y's are 7 but the last one is 4

8 0
2 years ago
Find all zeros x^3+2x^2+4x+21
dlinn [17]

Answer:

see explanation

Step-by-step explanation:

note when x = - 3

(- 3)³ + 2(- 3)² + 4(- 3) + 21 = - 27 + 18 - 12 + 21 = 0

hence x = - 3 is a zero and (x + 3) is a factor and dividing gives

\frac{x^3+2x^2+4x+21}{x+3} = (x + 3)(x² - x + 7)

For zeros equate to zero

(x + 3)(x² - x + 7) = 0

equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x² - x + 7 = 0 ← solve using quadratic formula

x = (1 ± \sqrt{1-28} ) / 2 = (1 ± 3i\sqrt{3} ) / 2

x = \frac{1}{2} ± \frac{3i\sqrt{3} }{2}

zeros are x = - 3, x = \frac{1}{2} ±\frac{3i\sqrt{3} }{2}


5 0
3 years ago
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