Question

X2 + (y - 1) 2 = 4 .............................

Answer 1

Answer:

Step-by-step explanation:

x²+(y-1)²=4

x²+y²+1-2y=4

x²+y²-2y=3

Answer 2

Answer:

$x=\pm \sqrt{6-2y}$

$y=\frac{1}{2} (6-x^2)$

Step-by-step explanation:

$x^2+(y-1)\cdot 2 =4$

$x^2+2y-2 =4$

$x^2+2y =6$

I will solve it for $x$

$x^2 =6-2y$

$x=\pm \sqrt{6-2y}$

Solving for $y$

$y=3-\frac{x^2}{2}$

$y=\frac{1}{2} (6-x^2)$