Answer:
-7
Step-by-step explanation:
Lets assume the number Peggy is thinking of be "x".
Now as given, when twice the number is added to three times one more than the number. We can write it as
∴ 
--- Equation 1
Again, it is given that Peggy gets the same result as when she multiplies four times one less than the number.
∴ 
-- equation 2
Next, we can equate both the equation 1 and 2 as it is given that result is same.
Let´s distribute 3 into 
and 4 into 
⇒ 
⇒ 
Subtract both side by 4x and 3
∴ 
∴ Peggy was thinking of -7
Since she needs 3 1/2 for 5, and you need to find one batch, get 3 1/2 and divide it by 5. Change 3 1/2 to an improper fraction (7/2). Now use KCS (keep change switch) Keep the 7/2, change division to multiplication, and switch 5/1 to 1/5. (7/2)•(1/5)
Answer:
4
Step-by-step explanation:
Let x = the number of years
In x years, Mai's mother's age will be: 28 + x
and Mai's age will be: 12 + x
Then, 28 + x = 2(12 + x)
Distribute the 2 28 + x = 24 + 2x
Subtract 24 from each side 4 + x = 2x
Subtract x from each side x = 4
In four years, Mai's mother will be twice Mai's age.
<em>Check:
</em>
28 + 4 = 2(12 + 4)
32 = 2 × 16
32 = 32
b = number of tickets sold before
a = number of tickets sold after
cost of a ticket = number of tickets times cost per ticket
before cost = 39.95b
after cost = 54.95a
total cost = 925000
39.95b + 54.95a = 925000
total number tickets = 20000
b + a = 20000
we have
39.95b + 54.95a = 925000
b + a = 20000
multiply second equation by -39.95 and add to first equation
39.95b + 54.95a = 925000
-39.95b-39.95a = -799000 +
0b+15a = 126000
15a = 126000
divide bot sides by 15
a = 8400
sub back
b + a = 20000
b+8400 = 20000
minus 8400 both sides
b = 11600
11,600 tickets sold before
8400 tickets sold after
