Car X traveled 3d distance in t time. Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t, the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.
In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.
Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.
We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.
Answer:
D) No, because of the way work is defined
Explanation:
The work done on an object is given by:
where
F is the force applied on the object
d is the displacement of the object
is the angle between the direction of the force and the displacement
From the formula, we observe that if there is no motion involved, then the displacement of the object is zero:
d = 0
As a result, the product in the formula is also zero, therefore the work done will be zero as well.
Answer:
The range of the projectile is 66.7 meters.
Explanation:
The range of a projectile is given by the following expression as :
..............(1)
The range can be calculated using equation (1). Putting the values of all parameters we get :
R = 66.7 meters
So, the range of the projectile is 66.7 meters. Hence, this is the required solution.
this is a direct current circuit.
