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dybincka [34]
3 years ago
10

A student solving a physics problem for the range of a projectile has obtained the expression

Physics
1 answer:
Alika [10]3 years ago
6 0

Answer:

The range of the projectile is 66.7 meters.

Explanation:

The range of a projectile is given by the following expression as :

R=\dfrac{v_o^2\ sin2\theta}{g}..............(1)

v_o=37.2\ m/s

\theta=14.1^{\circ}

g=9.8\ m/s^2

The range can be calculated using equation (1). Putting the values of all parameters we get :

R=\dfrac{(37.2)^2\ sin2(14.1)}{9.8}

R = 66.7 meters

So, the range of the projectile is 66.7 meters. Hence, this is the required solution.

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4 0
4 years ago
Is position a base or derived quantity?
amid [387]

Position is measured in meters (m), so it is a base quantity.

<h3>What is base quantity?</h3>

A base or fundamental  quantity is a physical quantity, in which other quantities are derived from.

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<h3>What is a derived quantity?</h3>

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Learn more about base quantities here: brainly.com/question/14480063

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8 0
2 years ago
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REY [17]

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