Answer:
![V = \frac{1}{3} \pi {r}^{2} h \\](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20h%20%5C%5C%20)
multiply either sides by 3:
![3 \times V = ( \frac{1}{3} \pi {r}^{2} h) \times 3 \\ \\ 3V = \pi {r}^{2} h](https://tex.z-dn.net/?f=3%20%5Ctimes%20V%20%3D%20%28%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20h%29%20%5Ctimes%203%20%5C%5C%20%20%5C%5C%203V%20%3D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20h)
divide either sides by πr² :
![{ \boxed{ \boxed{h = \frac{3V}{\pi {r}^{2} } }}} \\](https://tex.z-dn.net/?f=%7B%20%5Cboxed%7B%20%5Cboxed%7Bh%20%3D%20%20%5Cfrac%7B3V%7D%7B%5Cpi%20%7Br%7D%5E%7B2%7D%20%7D%20%7D%7D%7D%20%5C%5C%20)
These are false. Tami will need to work 11 weeks to get to her goal. To find out this problem, first take out the 100 from the 320 which then gives you 220. Then divide 220 by 20 which gives you 11. 1 is wrong because Tami does not have to work more than 21 weeks to get to her goal. 2 is also wrong because Tami does not need to save more that 11 weeks to get to her goal, she has to work 11 weeks only.
Use this version of the Law of Cosines to find side b:
b^2 = a^2 + c^2 − 2ac cos(B)
We want side b.
b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)
After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.
Try it....
Answer:
as per ur ques if we take x as number then we get algebraic expression as
2x - 4
brainliest?
It's D. scientific notation is in the form of n x 10^m, with n any number between 1 to 10.