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3 years ago

PLEASE HELPPPPPPP Find the square root of 1+8i so that the real part of your answer is positive

Mathematics

1 answer:

bonufazy [111]3 years ago

7 0

Answer:

Step-by-step explanation:

1+8i

i is the imaginary unit.

√8i is 2√2i

1+2√2i

3√2i

real part is 3

imaginary part is √2i

3 is positive

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In the United States nearly 8 x 10^9 text messages are sent everymonth About how many text messages is this! Find the primefacto

iris [78.8K]

$8\times10^9=2^{12}\times5^9$

1) Since in the USA 8 x 10 ^9 messages are sent every month, that means that approximately 8 billion messages are sent.

2) We can Prime factorize it:

Note that on the right side we've picked only prime numbers. In this case, 2 and 5.

So we can rewrite 8 x 10^9 as prime factors.

$8\times10^9=2^{12}\times5^9$

3) Hence, the answer is:

$8\times10^9=2^{12}\times5^9$

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1 year ago

5. Consider the diagram below. Solve for x.

mrs_skeptik [129]

Answer:

41 degrees

Step-by-step explanation:

The three angles need to add up to 180 degrees!

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3 years ago

A company purchased $10,000 of merchandise on January 5 with terms 2/10, n/30. On January 7, it returned $1,200 worth of merchan

s2008m [1.1K]

Answer:

C. Debit Accounts Payable $8,800; credit Merchandise Inventory, $176; credit Cash $8,624.

Step-by-step explanation:

Data given in the question is inconsistent with the options given.

Terms 2/10, n/30 means there is a discount of 2% is available on payment of due amount within discount period of 10 days after sale with net credit period of 30 days.

Purchases = $10,000

Returns = $1,200

Amount Due = $10,000 - $1,200 = $8,800

As the payment is made after discount period, so no discount will be availed. Full amount of $8,800 will be paid.

A similar and correct question is given below and answer is made accordingly.

A company purchased $10,000 of merchandise on January 5 with terms 2/10, n/30. On January 7, it returned $1,200 worth of merchandise. On January 12, it paid the full amount due. Assuming the company uses a perpetual inventory system, and records purchases using the gross method, the correct journal entry to record the payment on January 12 is:

Debit Accounts Payable $10,000; credit Merchandise Inventory $200; credit Cash $9,800.

Debit Merchandise Inventory $8,800; credit Cash $8,800.

Debit Accounts Payable $8,800; credit Merchandise Inventory, $176; credit Cash $8,624.

Debit Cash $1,600; credit Accounts Payable $1,600.

Debit Accounts Payable $8,624; credit Cash $8,624.

Solution

Terms 2/10, n/30 means there is a discount of 2% is available on payment of due amount within discount period of 10 days after sale with net credit period of 30 days.

Purchases = $10,000

Returns = $1,200

Amount Due = $10,000 - $1,200 = $8,800

As the payment is made within discount period, so discount will be availed

Discount = $8,800 x 2% = $176

Cash Paid = $8,800 - $176 = $8,624

5 0

3 years ago

Mrs. Smith is creating a rectangular flower bed such that the width is half of the

Brilliant_brown [7]

Answer:

As for this problem, we will first establish that the length of the flower bed be represented as x, the width of the flower bed be represented as x/2 ,and the area of the flower bed be taken as it is since it is given. We then follow the formula for area which is length multiplied to width which is:

A = LW

we then substitute them

34 square feet = x (x/2)

now all we need to do is find x first.

34 square feet = x squared / 2

now do a cross multiplication

68 square feet = x squared

then get the square root of both sides

8.246 feet = x

Since x is equal to the length of the flower bed, all we have to do to get the width of it is to divide it by 2. So...

W = x/2

W = 8.246 feet / 2

W = 4.123 feet

And since the problem asked it to find the width of the flower bed to the nearest tenth of a foot, the answer would be 4.1 ft.

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3 years ago

A college writing seminar increased its size by 50\PP, percent from the first to the second day. If the total number of students

Jobisdone [24]

Answer: There were 10 students in the class on the first day.

Step-by-step explanation:

Let x be the number of students of the first day.

Given: A college writing seminar increased its size by 50 percent from the first to the second day.

i.e. Number of students on second day = (Number of students on first day)+(50% of Number of students on first day)

= x +50% of x

= x+0.50x

= (1.50)x

=1.50x

Since, it is given that the total number of students in the seminar on the second day was 15.

i.e. $1.50x=15$

$\Rightarrow\ x=\dfrac{15}{1.5}\Rightarrow\ x=\dfrac{150}{15}\\\\\Rightarrow\ x=10$

Hence, there were 10 students in the class on the first day.

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4 years ago