Answer:
The probability is 1.
Explanation:
Despite that the he distribution is positively skewed, the distribution of sample means of one-bedroom apartments will still be a a normal distribution based on Central Limit Theorem.
Since we have
μ = mean = 2200
SD = standard deviation = 250
n = sample size = 50
Therefore,
Standard error = SD ÷ √n
= 250 ÷ √50
= 250 ÷ 7.07106781186548
= 35.3553390593274 approximately 35.36
Standardize xbar to z = (xbar - μ) ÷ (SD ÷ √n)
Therefore, we have:
P(xbar > 1,950) = P(z > (1,950 - 2200) ÷ 35.36)
= P(z > - 250 ÷ 35.36)
= P(z > -7.07) = 1
Therefore, the probability of selecting a sample of 50 one bedroom apartments is 1 which can be said to be certain.
Answer: Data gap analysis.
Explanation:
A Data gap analysis occurs when an organization evaluates it's available data, and seek methods of improving data collection to meet up with business expectations. Data gap analysis is done to ensure that, an organization has the right information to enable them run operations effectively.
Answer: ✓ an intermediate goal that affects a long-term goal
Answer:
Inventory cost will be $3
So option (b) is correct option
Explanation:
We have given that carrying and setup cost is $600
So carrying and setup cost = $600
And EOQ = 200 units
We have to find the inventory carrying cost per year
We know that inventory carrying cost is given by
inventory carrying cost 
So option (b) will be correct option