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melamori03 [73]
3 years ago
7

Which represents a perfect cube? 6 times 6 times 6 6 + 6 + 6 3 times 3 times 3 times 3 3 + 3 + 3 + 3 + 3

Mathematics
2 answers:
ankoles [38]3 years ago
7 0

Answer: 6 times 6 times 6

Step-by-step explanation: I did it on edg :)

mojhsa [17]3 years ago
4 0

Answer:

6 times 6 times 6

Step-by-step explanation:

6 x 6 = 6²

Therefore 6 x 6 x 6 = 6³

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Find the missing angle or find X?
Sindrei [870]
X = 60°
Because the square in the corner tells you that it is 90° (right angle)
So your equation to solve for x would be...
x + 30 = 90
Now you need to isolate the x.

Subtract both sides by 30.
x + 0 = 90 - 30
x = 60
3 0
2 years ago
Explain the process and the properties you have to use to solve the logarithmic equation: log(3)x + log(3)4 - 2 log(3)3 = 2
Akimi4 [234]

81/4

Step-by-step explanation:

log_{3}(  \frac{4x}{{3}^{2} }   )  = 2

{3}^{2}  =  \frac{4x}{ {3 }^{2} }

9=4x/9

81=4×

x=81/4

adding logs means elements are multiplied, subtracting means divide. number in front of log is raised to power

base of log is raised to power of element after =

element in log is then equal to log base raised to power

solve resulting equation

6 0
3 years ago
Find the value of x
anygoal [31]

Answer:

1

Step-by-step explanation:

As per circle theorem rule, ∠GDE is twice than ∠GFE

10x +94 = 2 × (x+51)

10x + 94 = 2x + 102

8x = 8

x = 1

∠GDE= 10x+94° = 104°

∠GFE= x + 51° = 52°

3 0
3 years ago
The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.
ehidna [41]
1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
     i) bisect the angles so m(ODC)=60°/2=30°

     ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, DO= \sqrt{ DC^{2}- OC^{2} }=  \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}= 
=\sqrt{9}* \sqrt{3} =3\sqrt{3}  (in)

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}==2*9 \sqrt{3}=18 \sqrt{3} (in^{2})

6 0
2 years ago
2x^2-13x+20=2x <br> 2<br> −13x+20
marta [7]

Answer:

Factor by grouping

( 2 x + 5 ) ( x + 4 )

6 0
3 years ago
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