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yan [13]
3 years ago
14

HELPPPPPPPP how do you do this?

Mathematics
1 answer:
V125BC [204]3 years ago
7 0
Solve for y like the top equation:
2y = -4ax + 11
2y/2 = -4ax/2 + 11/2
y = -2ax + 11/2

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V is the midpoint of UW. If UV = x + 2 and VW = 2x, what is VW?
Elan Coil [88]

Answer:

8 units

Step-by-step explanation:

x + 2 = 2x

2 = 2x - x

x = 2

uW = 2(2+2) = 8

3 0
2 years ago
Read 2 more answers
In a random sample of 64 people, 48 are classified as 'successful.' Determine the sample proportion of 'successful' people.
hichkok12 [17]

Answer:

The sample proportion of 'successful' people is \frac{3}{4}.

Step-by-step explanation:

The sample consist of 64 people and 48 of them are 'successful'. Hence, the proportion of 'successful' people is:

p = \frac{n}{N}

Where:

N - People that forms the sample, dimensionless.

n - People classified as 'successful', dimensionless.

Given that n = 48 and N = 64, the sample proportion of 'successful' people is:

p = \frac{48}{64}

p = \frac{3}{4}

The sample proportion of 'successful' people is \frac{3}{4}.

6 0
3 years ago
. One day the U.S. dollar was worth approximately 100 yen. An exchange of 2500 yen
Naya [18.7K]

Answer: $25

Step-by-step explanation:

2500/100 = 25

7 0
3 years ago
7a = 49 in multiplication way?<br> SHOW ALL WORK
Olegator [25]
A WOULD BE 7 BECAUSE 7 TIMES 7 EQUALS 49
8 0
3 years ago
Read 2 more answers
Start with the basic function f(x)=2x. If you have an initial value of 1, then you end up with the following iterations. f(1)=2*
denpristay [2]
<span>f(x)=2x

f(1)=2*1=2

f^2(1)=2*2*1=4

f^3(1) =2*2*2*1=8

1. If you continue this pattern, what do you expect would happen to the numbers as the number of iterations grows?

I expect the numbers continue growing multiplying each time by 2.

Check your result by conducting at least 10 iterations.

f^4(1) = f^3(1) * f(1) = 8*2 = 16

f^(5)(1) = f^4(1) * f(1) = 16 * 2 = 32

f^6 (1) = f^5 (1) * f(1) = 32 * 2 = 64

f^7 (1) = f^6 (1) * f(1) = 64 * 2 = 128

f^8 (1) = f^7 (1) * f(1) = 128 * 2 = 256

f^9 (1) = f^8 (1) * f(1) = 256 * 2 = 512

f^10 (1) = f^9 (1) * f(1) = 512 * 2 = 1024

2. Repeat the process with an initial value of −1. What happens as the number of iterations grows?

f(-1) = 2(-1) = - 2

f^2 (-1) = f(-1) * f(-1) = - 2 * - 2 = 4

f^3 (-1) = f^2 (-1) * f(-1) = 4 * (-2) = - 8

f^4 (-1) = f^3 (-1) * f(-1) = - 8 * (-2) = 16

f^5 (-1) = f^4 (-1) * f(-1) = 16 * (-2) = - 32

As you see the magnitude of the number increases, being multiplied by 2 each time, and the sign is aleternated, negative positive negative positive ...
</span>
4 0
3 years ago
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