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3 years ago

A number is chosen at random from 1 to 10. Find the probability of selecting factors of 4 and factors of 6

Mathematics

1 answer:

disa [49]3 years ago

5 0

4,6,8 because 4 times 2 is 8 and 6 times 1 equals 6 and 1 times 4 equals 4

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I got zero, but that’s wrong.

meriva

Answer:

Expected value is 4,000

Step-by-step explanation:

To find expected value ⇒ multiply the value by it's probability

40% × ( -25,000 ) = - 10,000

Breaking means neither add nor subtract a given amount

20% × 0 = 0

35% × 40,000 = 14,000

∴ Expected value = -10,000 + 14,000 = 4,000

LOSS: -10,000

BREAK EVEN: 0

WIN: 14,000

Expected value is 4,000

hope this helps....

3 0

3 years ago

At a high school, 14% of all students play a sport and 9% of all students play a

olga2289 [7]

Answer:

0.643

Step-by-step explanation:

Let, s = play a sport

c = participate in a club

P(s) = 0.14

P(s n c) = 0.09

probability that a student participates in

a club given that they also play a sport = P(c | s)

P(c | s) = P(c n s) / P(s)

P(c | s) = 0.09 / 0.14

P(c | s) = 0.64285

= 0.643

7 0

3 years ago

Let a = x2 + 4. Use a to find the solutions for the following equation:

Zepler [3.9K]

The solutions for x are -2, 0, 2

Solution:

Given that,

$\text { Let } a = x^2 + 4$

Given equation is:

$(x^2 + 4)^2 + 32 = 12x^2 + 48$

$(x^2 + 4)^2 + 32 = 12(x^2 + 4)$

$\text { Subtsitute } a = x^2 + 4 \text{ in above equation }$

$a^2 + 32 = 12a\\\\a^2 -12a + 32 = 0$

$\text{ Let us factorize the above equation }\\\\\text{ Splitting the middle term -12a as -4a - 8a we get, }$

$a^2 -4a - 8a + 32 = 0$

Taking "a" as common term from first two terms and taking "-8" as common from last two terms

$a(a-4)-8(a - 4) = 0$

$\text{Taking (a - 4) as common term, }\\\\(a - 4)(a - 8) = 0$

$\text{Equating to zero we get, }\\\\(a - 4) = 0 \text{ or } (a - 8) = 0\\\\a = 4 \text{ or } a = 8$

$\text{Now substitute the value of a = 8 and a = 4 in: }\\\\a = x^2 + 4$

$\text{ For a = 8: }\\\\a = x^2 + 4\\\\8 = x^2 + 4\\\\x^2 = 4\\\\x = \pm2\\\\x = +2 \text{ or } -2$

$\text{For a = 4: }\\\\a = x^2 + 4\\\\4 = x^2 + 4\\\\x = 0$

$\text{Thus solutions of } x \text{ are: }\\\\x = 0 \text{ or } x = 2 \text{ or } x = -2$

8 0

3 years ago

Im going to buy huaraches in womens (7.5) so do i order that size or order an 8?

lord [1]

Depends on your foot size. I’d go with the 8 as when you hike etc your feet can “swell” some.

3 0

3 years ago

Solve 2x-10=2 6 for x

strojnjashka [21]

Answer:

x=18

Step-by-step explanation:

isolate x to one side of the equation:

2x=26+10

2x = 36

divide by 2 for both sides

x = 36\2

x= 18

8 0

3 years ago