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3 years ago

The measures of the interior angles of a triangle are in the ratio of 1:2:3. the measure of the largest angle of the triangle is

1 answer:

8 0

The sum of interior angle of a triangle is 180 degrees

largest = 3/(1+2+3) × 180
largest = 3/6 × 180
largest = 90 degrees

The largest angle of the triangle is 90

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Select the graph of the quadratic function g(x) = 1/4x^2. Identify the domain and range

aniked [119]

Graph b
The domain is (-inf,inf)
The range is [0, inf)
Hope this helps!

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2 years ago

Find the sum 5.5+7.25-5.5+(-7.25) show your work

chubhunter [2.5K]

Answer:

5.5+7.25−5.5−7.25 = 0

Step-by-step explanation:

To be honest, you shouldn't have to show work for an equation like this. But this is the answer. Hope it helped.

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3 years ago

Read 2 more answers

Helpppp: Find the area of the parallelogram.

EleoNora [17]

Step-by-step explanation:

that is totally simple.

the area of a parallelogram is

baseline × height

basically the same as for a rectangle, just that in this more general form the height is no longer the other side.

in our case here

18×13 = 234 cm²

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2 years ago

What is 2/3 - 5/12? Show me the answer.

Aloiza [94]

Answer:

1/4 IS THE ANSWER I GOT AND THE DECIMAL FORM IS 0.25 HOPED IT HELPED

Step-by-step explanation:

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3 years ago

Lots of 40 components each are deemed unacceptable if they contain 3 or more defectives. The procedure for sampling a lot is to

MrRissso [65]

Answer:

The probability of founding exactly one defective item in the sample is P=0.275.

The mean and variance of defective components in the sample are:

$\mu=0.375\\\\\sigma^2=0.347$

Step-by-step explanation:

In the case we have a lot with 3 defectives components, the proportion of defectives is:

$p=3/40=0.075$

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).

The probability of having one defective in the sample is:

$P(k=5)=\binom{5}{1}p^1(1-p)^4=5*0.075*0.925^4=0.275$

b) The mean and variance of defective components in the sample is:

$\mu=np=5*0.075=0.375\\\\\sigma^2=npq=5*0.075*0.925=0.347$

The Chebyschev's inequality established:

$P(|X-\mu|\geq k\sigma)\leq \frac{1}{k^2}$

6 0

3 years ago