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LUCKY_DIMON [66]
3 years ago
9

Guys what is ascending order again ​

Mathematics
1 answer:
Allisa [31]3 years ago
4 0

Answer:

78

Step-by-step explanation:

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Which could be the value of x in the<br> triangle below?
hjlf
C could be the answer
8 0
3 years ago
Given a discriminat of 36 how many solutions with the quadratic function have?
alexira [117]

Answer:

2

Step-by-step explanation:

So!

If the d (discriminant)

d > 0 Then 2 solutions

d = 0 Then 1 solution

d < 0 Then none

36 > 0 so 2 solutions

8 0
3 years ago
Read 2 more answers
On a coordinate plane, point B(–6, 1) is translated to B prime(–3, –2). Indira uses these steps to find a rule to describe the t
Lunna [17]

Answer:

The rule of the translation is   (x,y) -----> (x+3,y-3)

The translation is 3 units at right and 3 units down

Step-by-step explanation:

we have that

The translation of point B to point B' is

B(-6,1) -----> B'(-3,-2)

so

(x,y) -----> (x+a,y+b)

B(-6,1) ----> (-6+a,1+b)

Find the value of a

-6+a=-3

solve for a

a=-3+6\\a=3

Find the value of b

1+b=-2

solve for b

b=-2-1\\b=-3

therefore

The rule of the translation is

(x,y) -----> (x+3,y-3)

That means ----> The translation is 3 units at right and 3 units down

3 0
3 years ago
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If f(1) =7 and f(n)=-5f(n-1)-n<br><br> then find the value of <br> f(4)
jolli1 [7]

Answer:

-914

Step-by-step explanation:

f(n)=-5f(n-1)-n

f(2)= -5f(1) -2 = -5(7) - 2 = -37

f(3) = -5f(2) - 3 = -5(-37) - 3 = 182

f(4) = -5f(3) - 4 = -5(182) - 4 = -914

4 0
3 years ago
I really need help with this one please
natka813 [3]

The distance from the sun is option 2 5.59 astronomical units.

Step-by-step explanation:

Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.

Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power \frac{3}{2} is on the variable we need to find so we multiply both the sides by an exponential power of \frac{2}{3} to be able to calculate 'a'.

P =  a^{\frac{3}{2} }, P^{\frac{2}{3} } = a^{\frac{3}{2}*\frac{2}{3}  },  P^{\frac{2}{3} } = a, 13.2^{\frac{2}{3} } = a = 5.58533 astronomical units.

Rounding it over to nearest hundredth we get 5.59 astronomical units.

6 0
3 years ago
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