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Radda [10]
4 years ago
15

The two figures are similar rectangles. Find the scale factor for the large rectangle to the small rectangle.

Mathematics
2 answers:
Elena L [17]4 years ago
7 0
It is B. Because “2” is 1/3 of 6 and 3 is 1/3 of 9.
guajiro [1.7K]4 years ago
3 0
Idk

I think itz a

2-3
6-9
6/2=3 9/3=3
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I need help on this.
Ivahew [28]

Answer:

Evaluate the terms inside of the parentheses

Step-by-step explanation:

According to PEMDAS, you always start solving an equation by answering what is inside of the parentheses first. (That's what the 'P' in PEMDAS stands for!)

Therefore, this is the correct answer.

8 0
4 years ago
Read 2 more answers
The diameter of a pearl is about 4 x 10-3cm and the diameter of an atom is about10-11m. How much larger than an atom is a pearl?
Ugo [173]

Answer:

  • D. 4 × 10⁶ times

Step-by-step explanation:

<u>The diameter of a pearl is </u>

  • 4 × 10⁻³cm = 4 × 10⁻⁵ m

<u>The diameter of an atom is</u>

  • 10⁻¹¹m

<u>How much larger than an atom is a pearl?</u>

  • 4 × 10⁻⁵ ÷ 10⁻¹¹ = 4 × 10⁻⁵⁺¹¹ = 4 × 10⁶ times

Correct option is D

5 0
3 years ago
If f(x) = -4x-8, find f(-3).
zvonat [6]

Answer:

f(-3)=3

Step-by-step explanation:

Plug in -3 for x.

f(-3)=-4(-3)-8

f(-3)=12-8

f(-3)=3

Hope this helps!

If not, I am sorry.

6 0
2 years ago
Please help me!!!!!!
dusya [7]

Answer:

The green box is -3

Step-by-step explanation:

You are reading from a graph, so it is more important perhaps, to pick clear points rather than easy to handle points.

The easiest two points you could use would be

(0,4)

(1, 1)

Slope

m = (y2 - y1)/(x2 - x1)

y2 = 4

y1 = 1

x2 = 0

x1 = 1

m = (4-1)/(0 -1)

m = 3/-1 = - 3

Y intercept

b = 4    from the point 0,4

Line

y = - 3x + 4

5 0
3 years ago
The constraints of a problem are listed below. What are the vertices of the feasible region? 4x + 3y &lt;= 122x + 6y &lt;= 15x &
Ira Lisetskai [31]

The feasible region is the region that comes from intersecting the different regions described by the equations that constrain the problem.

Let's take a look:

From this, we can conclude that the vertices of the feasible region are:

\begin{gathered} (0,0) \\ (0,2.5) \\ (1.5,2) \\ (3,0) \end{gathered}

4 0
1 year ago
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