A 1 = 57, a 2 = 61, a 3 = 65 ( arithmetic sequence )
a n = a 1 + ( n - 1 ) d
a 2 = a 1 + d
61 = 57 + d
d = 61 - 57
d = 4
a 9 = 57 + 8 * 4 = 57 + 36 = 93
Answer: Her score on the 9th assessment will be 93 points.
Answer:
<em>I</em><em> hope</em><em> it's</em><em> helps</em><em> you</em>
<em>have</em><em> a</em><em> nice</em><em> day</em>
Answer:
Right of X = 635.5
Step-by-step explanation:
By using the normal approximation to the Binomial random variable, we usually make use of continuity correction.
According to the rule of continuity;
P(X ≤ k) becomes P( X ≤ K + 0.5)
P(X < K) becomes P(X < K - 0.5)
P(X ≥ K) becomes P(X ≥ K - 0.5)
P(X > K) becomes P(X > K + 0.5)
P(X = K) becomes P(K - 0.5 ≤ X ≤ K + 0.5)
From the given question, Assume that we are to determine the probability that more than 635 Americans support the bill.
Then we use the > sign.
∴
P(X > K ) becomes P(X > K + 0.5)
P(X > 635) becomes P(X > 635 + 0.5)
⇒ P(X > 635.5) tot the right.
Right of X = 635.5
Answer:
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.
This means that 
If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
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