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Tcecarenko [31]
2 years ago
11

Its pppppppp pls answer meboth of the questionsBRAINLYEST

Mathematics
2 answers:
const2013 [10]2 years ago
5 0

1: D.

2: A.

Random text (I had to make the answer 20 characters or more.

kirill115 [55]2 years ago
5 0

Part 1:

D) 2 2/4

point B is <em>in between</em> the 3 and the half-point of 2. Which is 3/4 of 2.

3/4 + 2 = <u>2 3/4</u>

Part 2:

C) the 12th day

It will be when Matt has his 2nd quiz and Meg will have her 4th quiz.

6 x 2 = <u>12</u>

3 x 4 = <u>12</u>

(it could also be the 6th day [A)] when Matt has his first quiz and Meg has her second quiz)

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Ali Clara and Shane raise money for new books for the school library all Ellie rays 20% more than Clara and $58 more than Shan C
Vikki [24]

Answer:

a. $435

b. 33.33%

Step-by-step explanation:

P.S - The exact question is -

Let Clara raised money = x

As given,

Ali raised 20% more than Clara

⇒Ali raised money =  x + \frac{20}{100}x = x + \frac{1}{5} x = \frac{6}{5}x

Also given,

Clara raised \frac{1}{4} times more than Shan

Clara raised money = Shan raise money + \frac{1}{4} times shan raired money

⇒Clara raised money = \frac{5}{4}  Shan raised money

⇒Shan raised money =  \frac{4}{5} times Clara

⇒Shan raised money = \frac{4}{5} x

As given,

Ali raised $58 more than shan

⇒\frac{6}{5}x = \frac{4}{5}x + 58

⇒\frac{6}{5}x -\frac{4}{5} x = 58

⇒\frac{2}{5}x = 58

⇒x = (29)(5) = $145

∴ we get

Clara raised money = x = $145

Ali raised money = \frac{6}{5}x = $174

Shan raised money =\frac{4}{5} x  = $116

a.)

Total raised money = $145 + 174 + 116 = $435

b.)

Percentage of money Clara raised = \frac{145}{435}×100% = \frac{1}{3}×100% = 33.33%

3 0
2 years ago
A rain gutter is to be constructed from a metal sheet of width 48 cm by bending up one-third of the sheet on each side through a
Tomtit [17]
This is for 30cm not 48 but you can find out how to do it. This is an example

8 0
3 years ago
Exercise 1 (SW Chapter 5): Suppose that a researcher, using wage data on 250 randomly selected male workers and 280 female worke
kirza4 [7]
 b) answered. In what fraction of the samples would H0 from
3 0
3 years ago
The common difference in an arithmetic sequence is –2 and the first term is 47. What is the 29th term?
BlackZzzverrR [31]

An arithmetic sequence is an ordered list of numbers where the next number is found by adding on to the last number (ex: 2,5,8,11... is a sequence where 3 is added on to find the next number).

The equation for an arithmetic sequence is
A_{n}=A_{1}+(n-1)d

A_{n} is the "n-th" number in the sequence (ex:  is the first term in the sequence)
d is the number you add (common difference) to find the next number
The first number in the sequence is 47 so A_{1}=47
<span>d=-2 because the question gives you that
</span>
A_{n}=A_{1}+(n-1)d
<span>A_{29}=47+(29-1)(-2)
</span><span>A_{29}=47+(28)(-2)
</span><span>A_{29}=47+-56
</span><span>A_{29}=-9
</span>
The answer is A. -9.

<u>                                                       </u>

<span>The answer is C. 158</span>

For the second one, it gives you A_{1}=4 and <span>A_{}=18
You can use this to find d

</span><span>A_{n}=A_{1}+(n-1)d
</span><span>A_{3}=4+(3-1)d
</span><span>18=4+(3-1)d
</span><span>18=4+2d
</span><span>14=2d
</span><span>7=d
</span>
Now you can just solve using the equation normally.
<span>A_{n}=A_{1}+(n-1)d
</span><span>A_{23}=4+(23-1)(7)
</span><span>A_{23}=4+(22)(7)
</span><span>A_{23}=4+154
</span><span>A_{23}=158
</span>
The answer is C. 158
8 0
3 years ago
Read 2 more answers
you are rolling a 10-sided die with sides numbered 1-10. you keep rolling the die until you roll a prime number and then stop. l
evablogger [386]

The formula for E(x) would be SUM[ X(n)P(n)] from n = 1 to n = infinity until we get the prime number

In the given problem, a 10-sided die with 1-10 numbers is rolled until we get a prime number

Prime numbers between 1-10 = 2,3,5,7 (4 prime numbers)

Non - prime numbers = 1,4,6,8,9,10( 6 non-prime number)

Let X be the number of times the die is rolled

The probability of getting a prime =

P(Prime) = \frac{4}{10}

Now, the value of

E(X)=∑x.P(x) [ x-> {1, infinity}]

= P(1)X(1) +P(2)X(2)+P(3)X(3)+P(4)X(4)........+ P(n)X(n)

= 1.\frac{4}{10} + 2. \frac{6}{10}.\frac{4}{10} + 3.\frac{6}{10}.\frac{6}{10}\frac{4}{10} + 4. \frac{6}{10}.\frac{6}{10}.\frac{6}{10}.\frac{4}{10}.......

Hence, this is the value of E(x)

To learn more about Prime number, here

brainly.com/question/9315685

#SPJ4

4 0
2 years ago
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