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3 years ago

Its pppppppp pls answer meboth of the questionsBRAINLYEST

Mathematics

2 answers:

const2013 [10]3 years ago

5 0

1: D.

2: A.

Random text (I had to make the answer 20 characters or more.

kirill115 [55]3 years ago

5 0

Part 1:

D) 2 2/4

point B is in between the 3 and the half-point of 2. Which is 3/4 of 2.

3/4 + 2 = 2 3/4

Part 2:

C) the 12th day

It will be when Matt has his 2nd quiz and Meg will have her 4th quiz.

6 x 2 = 12

3 x 4 = 12

(it could also be the 6th day [A)] when Matt has his first quiz and Meg has her second quiz)

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Which of the following is a binomial?. c2 + c + 6. c2 - 16. -8c. c3 + 4c2 - 12c + 7. Which of the following is a monomial?. c2 +

vlabodo [156]

A monomial has one term, binomial has two terms, trinomial has three terms, and a polynomial has four or more terms.

Therefore, in the first question, c2-16 is the binomial while -8c is the monomial in the second question.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

7 0

3 years ago

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago

Please help please help

Mumz [18]

Answer:

angleEAF=angleBAC (शिर्षभिमुख कोण भएर)

10x+90+5x=180 (सरल कोण भएर)

or, 15x+90=180

or, 15x=180-90

or, 15x=90

or, x=90÷15

or, x=4

3 0

1 year ago

Read 2 more answers

Bentley spun a spinner with 4 equal sections labeled 1–4. The spinner landed on 1 three times, on 2 four times, on 3 six times,

OverLord2011 [107]

Answer:

Step-by-step explanation:

Experimental probability : (Number of times event occur / total number of trials)

Total Number of trials = (3 + 4 + 6 + 3) = 16

Experimental probability :

For 1: P(1) :

3/16

For 2 : P(2) :

4/16 = 1/4

For 3: P(3)

6 /16 = 3/8

For 4 : P(4)

3 / 16

Theoretical probability :

The Theoretical probability of 1, 2, 3 and 4 are the same ;

Theoretical probability =

(Required outcome / Total possible outcomes)

For each of 1 - 4

Theoretical probability = 1 /4

Experimental probability of P(2) = 1/ 4 and is Hence, the same as the Theoretical probability

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2 years ago

Which of the following is an example of a complex formula? A. =150*.05 B. =A1

marusya05 [52]

The answer is A. bc of the point

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3 years ago