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Oksi-84 [34.3K]
3 years ago
5

Sandy takes a day off once every 4 days, and Morgan takes a day off once every 10 days. Today, both of them have taken the day o

ff. How many days will it be until they have their next day off together?
Mathematics
2 answers:
Alenkasestr [34]3 years ago
4 0
Lets say that the day they both take off is day 0.
The next day Sandy takes off will be day 4, and Morgans will be day 10.
Sandy will take off 4, 8, 12, 16, and 20.
Morgan will take off 10, 20, 30, 40, and 50.

Both Morgan and Sandy take off day 20, so the next time they have a day off together will be in 20 days.
Lubov Fominskaja [6]3 years ago
4 0
The interval for each time they take the day off would be every 20 days.
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Solve the following system using elimination:
{-2 x + 2 y + 3 z = 0 | (equation 1)
{-2 x - y + z = -3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x - 3 y - 2 z = -3 | (equation 2)
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Multiply equation 2 by -1:
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{0 x+3 y + 2 z = 3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:
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Swap equation 2 with equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
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{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
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Multiply equation 3 by 5/8:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
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{0 x+0 y+z = 0 | (equation 3)


Divide equation 2 by 5:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
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Subtract 2 × (equation 2) from equation 1:
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Subtract 3 × (equation 3) from equation 1:
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Divide equation 1 by -2:
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{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1, y = 1, z = 0

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