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Diano4ka-milaya [45]
3 years ago
6

Please help me solve for x

Mathematics
1 answer:
sineoko [7]3 years ago
5 0
A) The ratio of the part of the triangle inside the circle and outside stays the same no matter what. So, I can set up an equality:
\frac{4}{6} = \frac{x}{5}

Solving for x gives us:
20=6x
x =  \frac{20}{6}= \frac{10}{3}

And that's your answer. 

Same thing for part b:

\frac{5}{3} = \frac{x}{4}
20=3x
x =  \frac{20}{3}

And there ya go. If you have any queries, I'd be happy to help.
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A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
What is negative 5 squared?
fiasKO [112]
Negative 5 squared is negative 25
3 0
4 years ago
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Julie printed out a picture of each of the five members of her favorite band to decorate her bedroom door. Each picture measures
Gnoma [55]
The answer is 175 square inches because you have to multiply 5in•7in to get 35inches per picture and since there are five you have to multiply by 35•5=175
8 0
3 years ago
Jonas bought 3 books. Each book was the same price. After using a $10-off coupon, the total charge was $20. Which equation can b
Brums [2.3K]

Answer:

3b-10=20

Step-by-step explanation:

3b-10=20

3b-10+10=20+10

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8 0
2 years ago
The point A(5.
NeX [460]

The point (6, 6) is the mid-point of A and B. Then the coordinate of the point B is (7, 5).

<h3>What is coordinate geometry?</h3>

Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of the line, etc.

Point A (5, 7) is reflected over the point (6, 6) and its image is point B. Then the point (6, 6) is the mid-point of the A and B. Then the coordinate of the point B will be

\rm (x_2 , y_2) = (2x -x _1, 2y - y_1)\\\\(x_2 , y_2) = (2 \times 6 - 5, 2 \times 6- 7)\\\\(x_2 , y_2) = (12-5,12-7)\\\\(x_2 , y_2) = (7, 5)

More about the coordinate geometry link is given below.

brainly.com/question/1601567

#SPJ1

5 0
2 years ago
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