Answer:
Option B is correct.
represents the population of the pack of wolves after t years
Step-by-step explanation:
The exponential growth function is given by;
......[1]
where
a represented the initial value
r represents the rate(in decimal)
t represents the time in years
As per the given statement: The population of a pack of wolves is 88. Also, the population is expected to grow at a rate of 2.5% each year.
⇒ a = 88 and r =2.5% = 0.025.
Substituting these values in equation [1], we have;
or
Therefore, the population model of the pack of wolves after t years is given by:
Rectangle:
2x+2x+2x+7+2x+7
8x+14
Hexagon:
2x+2x+x+x+x+8+x+6
8x+14
They’re equal
Answer:
The proportion of temperatures that lie within the given limits are 10.24%
Step-by-step explanation:
Solution:-
- Let X be a random variable that denotes the average city temperatures in the month of August.
- The random variable X is normally distributed with parameters:
mean ( u ) = 21.25
standard deviation ( σ ) = 2
- Express the distribution of X:
X ~ Norm ( u , σ^2 )
X ~ Norm ( 21.25 , 2^2 )
- We are to evaluate the proportion of set of temperatures in the month of august that lies between 23.71 degrees Celsius and 26.17 degrees Celsius :
P ( 23.71 < X < 26.17 )
- We will standardize our limits i.e compute the Z-score values:
P ( (x1 - u) / σ < Z < (x2 - u) / σ )
P ( (23.71 - 21.25) / 2 < Z < (26.17 - 21.25) / 2 )
P ( 1.23 < Z < 2.46 ).
- Now use the standard normal distribution tables:
P ( 1.23 < Z < 2.46 ) = 0.1024
- The proportion of temperatures that lie within the given limits are 10.24%
Discriminant is the value b^2 - 4*a*c
(-3)^2 - 4*2*1
9 - 8 = 1
Answer:
Step-by-step explanation:
The ratio of copies printed is ...
X : Y = 1 : 2
so the ratio of the number printed by machine X to the total is ...
X : (X+Y) = 1 : (1+2) = 1 : 3
1/3 of the 159 copies were printed by machine X, so it printed ...
(159)(1/3) = 53
Twice that many were printed by machine Y, so it printed ...
2·53 = 106
Machine X printed 53 copies; machine Y printed 106 copies.
