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Lelechka [254]
3 years ago
11

What is the equation of a line, in point- slope form, that passes through (5, −3)(5, −3) and has a slope of 2323 ? y+5=23(x−3)y+

5=23(x−3) y−5=23(x+3)y−5=23(x+3) y+3=23(x−5)y+3=23(x−5) y−3=23(x+5)
Mathematics
2 answers:
Marta_Voda [28]3 years ago
7 0
Youyou havehave aa seriousserious doubledouble pastepaste problemproblem

the equation of the line that passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given

the point is (5,-3) and the slope is 23 (or it could be 2/3)
x1=5
y1=-3
y-(-3)=23(x-5)
y+3=23(x-5) is answer
Bumek [7]3 years ago
4 0

Answer:

y+3=23(x-5) is the answer

Step-by-step explanation:

Just took the test im k12

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Answer:

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Step-by-step explanation:

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Solve for qqq. 3\left(q+\dfrac43\right) = 23(q+ 3 4 ​ )=2<br>pls answer this
enyata [817]

Answer:

<h2>19/3</h2>

Step-by-step explanation:

Given the expression 3\left(q+\dfrac43\right) = 23, we are to find the value of q;

3\left(q+\dfrac43\right) = 23\\on\ expansion\\\\3q + 4/3(3) = 23\\\\3q+4 = 23\\\\subtract \ 4\ from \ both\ sides \ of \ the \ equation\\\\3q+4-4 = 23-4\\\\3q = 19\\\\Diviide \both\ sides \ by \ 3\\\\3q/3 = 19/3\\\\q = 19/3

Hence the value of q is 19/3

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3 years ago
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BaLLatris [955]
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Answer: Choice B)  \sqrt{14}

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negative times negative = positive.

8 0
3 years ago
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