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valentinak56 [21]
4 years ago
6

One fifth of a number is subtracted from four fifth of the same number. If the result is 9, what is the number. ​

Mathematics
1 answer:
JulsSmile [24]4 years ago
8 0

Let x be the unknown number. One fifth of this number is x/5, one fourth of this number is x/4. So, we have

\dfrac{x}{4}-\dfrac{x}{5} = \dfrac{5x-4x}{20} = \dfrac{x}{20}

We know that this difference equals 9, so we have

\dfrac{x}{20}=9

Multiply both sides by 20 to get

x=180

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This is algebra 1 id appreciate it if you could help me thx!
Orlov [11]

Answer:

Option 4: 0

Step-by-step explanation:

Given the function, f(x) = 3x, and the domain. {-3, 1, 4}:

Substitute the values of each domain as inputs into the function:

<h3>x = -3</h3>

f(-3) = 3(-3)

f(-3) = -9

<h3>x = 1</h3>

f( 1 ) = 3( 1 )

f( 1 ) = 3

<h3>x = 4</h3>

f(4) = 3(4)

f(4) = 12

Therefore, the correct answer is option 4) 0, because there is no input value that provides an output of 0. You were only given three domain values that provided its corresponding outputs.

7 0
3 years ago
A recursive rule for an arithmetic sequence is a1=4;an=an−1−3 . What is the explicit rule for this sequence? Enter your answer i
Westkost [7]

Answer:

The explicit rule for the arithmetic sequence is given by:

a_n = a_1+(n-1)d       ......[1]

where,

a_1 is the first term

n is the number of terms and

d is the common difference for two consecutive terms.

As per the statement:

A recursive rule for an arithmetic sequence is:

a_1 = 4

a_n = a_{n-1}-3

The recursive formula for the arithmetic sequence is given by:

a_n = a_{n-1}+d

then;

On comparing we get;

d = -3

Substitute the given values in [1] we have;

a_n = 4+(n-1)(-3)

⇒a_n = 4 -3n+3 = 7-3n

Therefore, the explicit rule for this sequence is, a_n = 7 -3n

5 0
3 years ago
Help with this immediately​
Reptile [31]

Answer:

100 - 89.6 = 10.4

This is the answer.

4 0
3 years ago
Read 2 more answers
Actor the expression 16x+8x+1 16x 28x +11-​
Gwar [14]
<h3>Explanation:</h3>

\large \purple {\sf { {16x}^{2}  + 8x + 1}}

\large \pink {\sf { =  {(4x)}^{2}  + 2(4x)(1) +  {(1)}^{2}}}

\large \orange {\sf { = {(4x + 1)}^{2} }}

<h2>Answer:</h2>

\large \green {\sf {{16x}^{2}  + 8x + 1 =  {(4x + 1)}^{2}}}

6 0
3 years ago
Please help me with these factoring problems. Please help me solve. I can't do these!!
aleksley [76]
Simple...

you have: 

1.) -8x-16  --->>>

Factor out a -8 -->>

-8(x+2)

2.)9d+15db --->

Factor out 3d -->

3d(3+5b)

3.) 2a-9ax-->>

Factor out -a -->

-1a(9x-2)

Thus, your answer.
3 0
3 years ago
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