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Gre4nikov [31]
3 years ago
11

A town has 100 homes in it. According to a census, the actual distribution of pets in these homes gives a median of 0.8 pets and

a mode of 1 pet. A student surveys 10 of these homes and finds nearly identical data: a median of 0.7 pets per home with a mode of 1. The student’s small survey gives nearly the same results as the much larger census because the
A) town itself is very small.

B) student simply got lucky.

C) student made a miscalculation

D) variation in the number of pets per house is small.
Mathematics
2 answers:
stellarik [79]3 years ago
6 0
The nest answer would be c> hope this helps 
natulia [17]3 years ago
6 0
The answer is D. I think.
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ΔABC has coordinates A(8, −4), B(2, 2), and C(0, −6). Write the coordinates of the image after a dilation with a scale factor of
MakcuM [25]

Answer:

formula= (kx,ky)

where k = scale factor

= A((8,-4)

= A= (8×12,-4×12)

<u>A= (96,-48)</u>

B= (2,2)

= (2×12,2×12)

<u>B= (24,24)</u>

C= (0,-6)

= (0×12,-6×12)

<u>C= (0,-72)</u>

4 0
2 years ago
If 2x + 5 = 8x, then 12x = ?A.5B.10C.15D.20
butalik [34]
<h2>Answer:</h2>10.\text{ Option B is correct}

<h2>Explanation:</h2>

Given the equation expressed as:

2x+5=8x

First, we need to calculate the value of "x" from the given expression.

Step 1: Given the equation 2x + 5 = 8x

Step 2: Subtract 5 from both sides:

\begin{gathered} 2x+5-5=8x-5 \\ 2x+\cancel{5}-\cancel{5}=8x-5 \\ 2x=8x-5 \end{gathered}

Step 3: Subtract 8x from both sides

\begin{gathered} 2x-8x=8x-8x-5 \\ -6x=\cancel{8x}-\cancel{8x}-5 \\ -6x=-5 \end{gathered}

Step 4: Divide both sides by -6

\begin{gathered} \frac{-6x}{-6}=\frac{-5}{-6} \\ x=\frac{5}{6} \end{gathered}

Step 5: Get the value of 12x. Substitute x = 5/6 into the expression to have:

\begin{gathered} 12x=12(\frac{5}{6}) \\ 12x=\cancel{12}^2(\frac{5}{\cancel{6}^1}) \\ 12x=2\times5 \\ 12x=10 \end{gathered}

Therefore the value of 12x is 10

3 0
11 months ago
Each observation indicates the primary position played by the Hall of Famers: pitcher (P), catcher (H), 1st base (1), 2nd base (
gregori [183]

Answer:

a. See below for the Frequency and Relative frequency Table.

b. Pitcher (P) is the position provides the most Hall of Famers.

c. 3rd base (3) is the position that provides the fewest Hall of Famers.

d. R is the outfield position that provides the most Hall of Famers.

e. Th number of Hall of Famers of Infielders which is 16 is less than the 18 Hall of Famers of those of outfielders.

Step-by-step explanation:

Note: This question not complete. The complete question is therefore provided before answering the question as follows:

Data for a sample of 55 members of the Baseball Hall of Fame in Cooperstown, New York, are shown here. Each observation indicates the primary position played by the Hall of Famers: pitcher (P), catcher (H), 1st base (1), 2nd base (2), 3rd base (3), shortstop (S), left field (L), center field (C), and right field (R).

L P C H 2 P R 1 S S 1 L P R P

P P P R C S L R P C C P P R P

2 3 P H L P 1 C P P P S 1 L R

R 1 2 H S 3 H 2 L P

a. Use frequency and relative frequency distributions to summarize the data.

b. What position provides the most Hall of Famers?

c. What position provides the fewest Hall of Famers?

d. What outfield position (L, C, or R) provides the most Hall of Famers?

e. Compare infielders (1, 2, 3, and S) to outfielders (L, C, and R).

The explanation of the answers is now provided as follows:

a. Use frequency and relative frequency distributions to summarize the data.

The frequency is the number of times a position occurs in the sample, while the relative frequency is calculated as the frequency of each position divided by the sample size multiplied by 100.

Therefore, we have:

<u>Frequency and Relative frequency Table  </u>

<u>Position</u>           <u>Frequency </u>         <u> Relative frequency (%) </u>

P                               17                             30.91%

H                               4                               7.27%

1                                5                               9.09%

2                               4                               7.27%

3                               2                               3.64%

S                               5                               9.09%

L                               6                               10.91%

C                              5                                 9.09%

R                        <u>      7     </u>                          <u>  12.73% </u>

Total                  <u>     55   </u>                          <u>   100%   </u>

b. What position provides the most Hall of Famers?

As it can be seen from the frequency table in part a, Pitcher (P) has the highest frequency which is 17. Therefore, Pitcher (P) is the position provides the most Hall of Famers.

c. What position provides the fewest Hall of Famers?

As it can be seen from the frequency table in part a, 3rd base (3) has the lowest frequency which is 2. Therefore, 3rd base (3) is the position that provides the fewest Hall of Famers.

d. What outfield position (L, C, or R) provides the most Hall of Famers?

As it can be seen from the frequency table in part a, we have:

Frequency of L = 6

Frequency of C = 5

Frequency of R = 7

Since R has the highest frequency which is 7 among the outfield position (L, C, or R), it implies that R is the outfield position that provides the most Hall of Famers.

e. Compare infielders (1, 2, 3, and S) to outfielders (L, C, and R).

Total frequency of infielders = Frequency of 1 + Frequency of 2 + Frequency of 3 + Frequency of S = 5 + 4 + 2 + 5 = 16

Total frequency of outfielders = Frequency of L + Frequency of C + Frequency of R = 6 + 5 + 7 = 18

The calculated total frequencies above imply that number of Hall of Famers of Infielders which is 16 is less than the 18 Hall of Famers of those of outfielders.

5 0
3 years ago
To complete a task in 15 days, a company has 4 people each working 8 hours a day. The company
Klio2033 [76]

Answer:

Let's suppose that each person works at an hourly rate R.

Then if 4 people working 8 hours per day, a total of 15 days to complete the task, we can write this as:

4*R*(15*8 hours) = 1 task.

Whit this we can find the value of R.

R = 1 task/(4*15*8 h) = (1/480) task/hour.

a) Now suppose that we have 5 workers, and each one of them works 6 hours per day for a total of D days to complete the task, then we have the equation:

5*( (1/480) task/hour)*(D*6 hours) = 1 task.

We only need to isolate D, that is the number of days that will take the 5 workers to complete the task:

D = (1 task)/(5*6h*1/480 task/hour) = (1 task)/(30/480 taks) = 480/30 = 16

D = 16

Then the 5 workers working 6 hours per day, need 16 days to complete the job.

b) The assumption is that all workers work at the same rate R. If this was not the case (and each one worked at a different rate) we couldn't find the rate at which each worker completes the task (because we had not enough information), and then we would be incapable of completing the question.

4 0
3 years ago
Which of the following are techniques used in geometric constructions with
Alisiya [41]
Answer= A
Explication
6 0
3 years ago
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