Start at 4, add the next odd number. What is the algebraic expression?

Write an equation passing through the point and perpendicular to the given line: (-3,5);y = 3/4x-4

balandron [24]

Hey!

So the first thing we realize is that it says that the equation is perpendicular to the line, meaning that the slope of the line is the negative reciprocal of the slope of the line you are given. Since we are given the slope of this line as 3/4 we can take the negative reciprocal of this to get -(4/3).

Now that we have the slope and a point on the line you can plug those into the equation y = mx + b to find b. The slope of the line is m and the point contains the x and y values.

5 = -(4/3)(-3) + b

5 = 4 + b

1 = b

Since we have the y-intercept and the slope now we can plug that into the slope-intercept form equation to get the equation we need:

y = -(4/3)x + 1

7 0

3 years ago

When testing the claim that p 1p1equals=p 2p2, a test statistic of zequals=2.04 is obtained. Find the p-value obtained from th

AURORKA [14]

Answer:

0.0414 with an upper tailed test

Step-by-step explanation:

Claim: P1P1 = P2P2

The above is a null hypothesis

The alternative hypothesis for a two-tailed test would be:

P1P1 \=/ P2P2

Where "\=/" represents "not equal to".

Using a z-table or z-calculator, we derive the p-value (probability value) for the z-score 2.04

With an upper tailed test, the

2 × [probability that z>2.04] = 2[0.0207] = 0.0414

This is the p-value for the test statistic.

Focus is on the alternative hypothesis.

8 0

3 years ago

Help need plzzzzzzzzz

Vilka [71]

Answer:

24

Step-by-step explanation:

3 0

2 years ago

Tess and Alice are both on the swim team. Last practice, they each swam laps for the same amount of time, but Tess finished more

beks73 [17]

Answer:

wait so what is the numbers of distance they have swam?

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

-Dominant- [34]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is tested if it does not outlast by more than 2 hours, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is tested if it outlasts by more than 2 hours, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has mean and standard deviation given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a right-tailed test, as we are testing if the subtraction is greater than a value, with a 0.05 significance level and 12 + 12 - 2 = 22 df is given by $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0

2 years ago