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3 years ago

Can someone help me with this problem

Mathematics

1 answer:

Troyanec [42]3 years ago

3 0

THE ANSWER IS
mTQ=69
mQR=155
mTS=111
mSQR=335
mRQT=224

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Subtract (5x^2-5) from the sum (x^2-9x+2) and (4x^2-5x+1)

Ivan

Assignment: $\bold{Solve \ Equation: \ \left(x^2-9x+2\right)+\left(4x^2-5x+1\right)-\left(5x^2-5\right)}$

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Answer: $\boxed{\bold{-14x+8}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Remove Parenthesis: (a) = a

$\bold{x^2-9x+2+4x^2-5x+1-\left(5x^2-5\right)}$

[ Step Two ] Simplify $\bold{-\left(5x^2-5\right)}$

$\bold{-5x^2+5}$

[ Step Three ] Rewrite Equation

$\bold{x^2-9x+2+4x^2-5x+1-5x^2+5}$

[ Step Four ] Simplify $\bold{x^2-9x+2+4x^2-5x+1-5x^2+5}$

$\bold{-14x+8}$

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$\bold{\rightarrow Mordancy \leftarrow}$

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4 years ago

A rectangle has a height of 777 and a width of 2x^2-32x

Murljashka [212]

<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write clear questions in order to get good and exact answers. Here I'll assume the data given in a comment above. So:

$H:height \\ \\ W:Width \\ \\ \\ H=7 \\ \\ W= 2x^2-32x+2$

We know that the area (A) of any rectangle is given by:

$A=H\times W \\ \\ A=7(2x^2-32x+2) \\ \\ \\ Expanding: \\ \\ A=(7)(2x^2)-(7)(32x)+(7)(2) \\ \\ \boxed{A=14x^2-224x+14}$

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Should always be presented while using a factor 2

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3 years ago