Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
4 2/3 / 1/16 =
14/3 • 16 =
224/3 =
74 2/3
She can't make a dress out of 2/3 material so she can only make 74 dresses
Since V = (4/3) * pi * R^3
If R is halved, V' will reduce by a ratio of (1/2)^3 = 1/8
So V' = (1/8)V
Answer:
109.33
Step-by-step explanation:
given that the population has a distribution with a mean of 110 and a standard deviation of 8
Sample size n = 40
Std error of sample mean = std dev/square root of sample size
= 
From std normal distribution table we find that 30th percentile for Z is
-0.5244
Corresponding x score =
30th percentile = 109.33663
=109.33
