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Crank
3 years ago
6

Write 9/12 as a sum of unit fractions

Mathematics
1 answer:
denpristay [2]3 years ago
7 0
The sum of a unit fraction is 1/12
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<img src="https://tex.z-dn.net/?f=n%20%3D%2020" id="TexFormula1" title="n = 20" alt="n = 20" align="absmiddle" class="latex-form
devlian [24]

Answer:

s=10

Step-by-step explanation:

Basically, the range rule-of-thumb is that the range is generally about four times the standard deviation.

<u>First, we find the range:</u>

Range=Maximum-Minimum

Range=100-60

Range=40

<u>Next, divide the range by 4 to get the standard deviation</u>

Range=4(Standard Deviation)

40=4(Standard Deviation)

10=Standard Deviation

Therefore, s=10, which is the standard deviation

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2 years ago
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Please someone help me with this problem?
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X=B^1 + b^7 . i found my answer by you need to find the slope of the numbers between the table.
4 0
3 years ago
ABCD is a quadrilateral inscribed in a circle, as shown below:
malfutka [58]

Answer:

Option 4: <u>(2x + 16)° + (x)° = 180°</u>

Step-by-step explanation:

See the attached figure.

For a quadrilateral inscribed in a circle

The opposite angles are supplementary.

So, ∠D + ∠B = 180°

From the figure:

∠B = x°  and ∠D = (2x+16)°

∴  <u>(2x + 16)° + (x)° = 180°</u>

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2 years ago
Convert the angle 0=17pie/18 radians to degrees.<br> Express your answer exactly.
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2 years ago
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Suppose that you are an elementary school teacher and you are evaluating the reading levels of your students. You find an indivi
aleksklad [387]

Answer:

The child's reading level is at the 3.4th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

You do some research and determine that the reading rates for their grade level are normally distributed with a mean of 90 words per minute and a standard deviation of 24 words per minute.

This means that \mu = 90, \sigma = 24

You find an individual that reads 46.4 word per minute. At what percentile is the child's reading level?

The percentile is the p-value of Z when X = 46.4, multiplied by 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{46.4 - 90}{24}

Z = -1.82

Z = -1.82 has a p-value of 0.034.

0.034*100 = 3.4

The child's reading level is at the 3.4th percentile.

6 0
2 years ago
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